Given that m = 19 kg and 0 = 51, solve T2. Note: Round off final answer to 4 decimal places.

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A: (a) Using Gauss’s law ∮E→·ds→=Qε0Eoutside2πrl=λlε0Eoutside=λ2πrε0=λ2πr8.854×10-12 F/m=1.8×1010λr

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A: Solution attached in the photo....

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Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”