Given that kinetic energy K= 100 eV = 100 (1.6x10-J) Angle 8= 1° mass of the electron m =9.11x10-31kg planck's constant h = 6.626x10-* Js The wavelenght of the electron is 2mK (6.626x10* Js) J2(9.11x10)(100 (1.6×10-ºC)) We have the consdition for the central maxima is d sin e=m A The slit wi dth is d: sin e Herem= 1 Substitute the values for d.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Given that
kinetic energy K= 100 eV
= 100 (1.6×10J)
Angle 8= 1°
mass of the electron m =9.11x10-31kg
planck's constant h =6.626x10-* Js
The wavelenght of the electron is
2mK
(6.626×10* Js)
J2(9.11x10)(100 (1.6x10-C))
We have the consdition for the central maxima is
d sin e=m 2
The slit wi dth is
sine
Herem =1
Substitute the values for d.
II
Transcribed Image Text:Given that kinetic energy K= 100 eV = 100 (1.6×10J) Angle 8= 1° mass of the electron m =9.11x10-31kg planck's constant h =6.626x10-* Js The wavelenght of the electron is 2mK (6.626×10* Js) J2(9.11x10)(100 (1.6x10-C)) We have the consdition for the central maxima is d sin e=m 2 The slit wi dth is sine Herem =1 Substitute the values for d. II
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