Given that F (s) = ¹ + (+2+³) e¯²s, then f(t) is. S a. f(t) = 1 = t² + 4t + 5 b. f(t) = 1 = t+1 c. f(t) = 1 d. f(t) = 1 = t² + 1 0
Given that F (s) = ¹ + (+2+³) e¯²s, then f(t) is. S a. f(t) = 1 = t² + 4t + 5 b. f(t) = 1 = t+1 c. f(t) = 1 d. f(t) = 1 = t² + 1 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Given that F (s) = + (+/+) e¯²s, then f(t) is_
S
a.
f(t) = 1
0 < t < 2
= = t² + 4t + 5
t≥ 2
b. f(t) = 1
0<t <2
= t + 1
t≥ 2
C.
f(t) = 1
d. f(t) = 1
= t² + 1
0 < t < 2
t≥ 2
0 < t < 2
t≥ 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2dd43c88-0b41-4097-ac49-c73a1b20ae11%2Fcd92a8ba-0f42-4bac-8252-7f2af0920d7f%2Fv9cbq1r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given that F (s) = + (+/+) e¯²s, then f(t) is_
S
a.
f(t) = 1
0 < t < 2
= = t² + 4t + 5
t≥ 2
b. f(t) = 1
0<t <2
= t + 1
t≥ 2
C.
f(t) = 1
d. f(t) = 1
= t² + 1
0 < t < 2
t≥ 2
0 < t < 2
t≥ 2
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