Given that coefficient of curvature = 1.4, D30 = 3 mm, D₁0 = 0.6 mm. 10 Based on this information of particle size distribution for use as subgrade, this soil will be taken to be (a) uniformly-graded sand (b) well-graded sand (c) very fine sand (d) poorly-graded sand

Given that coefficient of curvature = 1.4, D30 = 3 mm, D₁0 = 0.6 mm. 10 Based on this information of particle size distribution for use as subgrade, this soil will be taken to be (a) uniformly-graded sand (b) well-graded sand (c) very fine sand (d) poorly-graded sand

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter2: Geotechnical Properties Of Soil

Section: Chapter Questions

Problem 2.6P: In AASHTO, which group are the following soil likely to fail into? a. A well-graded gravel with...

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Weight-Volume relationships

Weight is defined as the quantity of matter contained in a body. Weight can also be defined as the force acting on a body due to gravity. Mathematically, weight can be defined as-

Question

Given that coefficient of curvature = 1.4,
D30 = 3 mm, D₁0 = 0.6 mm.
10
Based on this information of particle size
distribution for use as subgrade, this soil will be
taken to be
(a) uniformly-graded sand
(b) well-graded sand
(c) very fine sand
(d) poorly-graded sand

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In AASHTO, which group are the following soil likely to fail into? a. A well-graded gravel with approximately 10% fines b. A well-graded sand with approximately 10% fines c. A uniform fine sand d. A high plastic clay
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A synthetic soil is made by mixing: 400 plastic spheres with Gs = 0.8 and diameter = 5mm, and 250 glass spheres with Gs = 2.65 and diameter = 4mm. %3D %3D According to the USCS, would the synthetic soil classify as a sand or as a gravel? Show work to support your answer.
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Q.1. Select the right answer of the following: 1. The void ratio of soil can be: a. greater than void ratio b. less than void ratio c. equal to void ratio d. no one 2. When Gravel had coefficient of uniformity of 3, the soil could be according USCS: a. GW b. GP c. SP d. any one of them 3. In a wet soil mass, air occupies 1/6 of volume and water occupies 1/3 of volume. The void ratio is: a. 0.25 b. 0.50 4. For the soil with LL= 45%, PL = 25% and water content = 15% the liquidity index is: B.0 с. 1.50 d. 1.00 a.0.6 5. The type of unit weight of soil s depends on: с. 1 dinone of them а. е b. n c. YW d. S 6. Soil has LL of 30, the corresponding plasticity index given by A-line: a. 7.3 b. 7.5 c. 9.0 d. 9.5 7. The porosity in of soil is function of: c. Vv & n P.= L.L-PL 12:45-25=2 a. Vv&Vs b. Vv& Vt d. Vs & n 8. For a soil deposit having n= 33% and G 2.6, ysaturated= 15KN/m3, S is: %3D а. 1.0 b. 1.05 с. 1.07 d. 1.10 10. When saturation in soil sample occurs, the degree of saturation: a.…
In a soil specimen, 70% of particles are passing through 4.75 mm sieve and 40% of particles are passing 0.075 mm sieve. Its uniformity coefficient is 8 and coefficient of curvature is 2. As per USCS, this soil is classified as: a.SP b.GP c.GW d.SW
Q1: Classify the below soil according to Unified Soil Classification System (USCS) and .the AASHTO System Sieve No. sieve Diameter 4.75 2 1.18 06 pass % 65 4. 10 52 40 16 30 40 26 0.425 0.25 0.075 21 60 14 200 10 And the Liquid Limit (LL) = 35. Plastic Limit (PL) = 18 100 90 80 70 60 50 40 30 20 10 0.01 0.1 10 Sieve Dia mm passing%
Given the coefficient of curvature =1.4 ‚D_{30}=3mm, D_{10} = 0.6 mm. Based on this information of particle size distribution for use as subgrade, this soil is classified as-
Read the question carefully and give me right solution with clear calculations