Given that at 25.0 °C K for HCN is 4.9 x 10-10 and Kb for NH3 is 1.8 x 10-5. calculate Kb for CN and • • K, for NH₂¹. Enter the K, value for CN followed by the K₂ value for NH4+, separated by a comma, using two significant figures. ▸ View Available Hint(s)

Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Acid-Base Properties of Salt Solutions

**Salt is an ionic compound** that is produced when a cation and an anion from an acid-base reaction combine, and solutions of salts can be neutral, acidic, or basic, depending on the acid-base properties of the constituent cations and anions.

Since strong acids and bases completely ionize in solution, the reaction essentially runs to completion forming the salt. Therefore, salts formed by the reaction of a strong acid with a strong base are neutral. NaCl formed by the neutralization of NaOH and HCl is a neutral salt.

Salts formed by the reaction of a strong acid with a weak base are acidic, and salts formed by the reaction of a weak acid with a strong base are basic. This is due to the equilibrium the conjugate has with its acid or base. For example, sodium bicarbonate NaHCO₃ contains the conjugate of the weak acid H₂CO₃. The conjugate will reform the acid through the equilibrium:

\[ \text{HCO}_3^- \, (\text{aq}) + \text{H}_2\text{O} \, (\text{aq}) \leftrightarrows \text{H}_2\text{CO}_3 \, (\text{aq}) + \text{OH}^- \, (\text{aq}) \]

and, thus, acts as a weak base. A solution of NaHCO₃ yields a basic solution.

If a salt is derived from a weak acid and a weak base, the pH of the solution depends on the relative acid strength (\(K_a\)) of the cation and base strength (\(K_b\)) of the anion. If \(K_a > K_b\), the solution of the salt is acidic. If \(K_a < K_b\), it is basic. If \(K_a \approx K_b\), it is neutral.

### Part A

Given that at 25.0°C:

- \(K_a\) for HCN is \(4.9 \times 10^{-10}\) and
- \(K_b\) for NH₃ is \(1.8 \times 10^{-5}\).

Calculate:
- \(K_b\) for CN⁻ and
- \(K_a\) for NH₄⁺.

Enter the \(K_b\) value for CN⁻ followed by the
Transcribed Image Text:### Acid-Base Properties of Salt Solutions **Salt is an ionic compound** that is produced when a cation and an anion from an acid-base reaction combine, and solutions of salts can be neutral, acidic, or basic, depending on the acid-base properties of the constituent cations and anions. Since strong acids and bases completely ionize in solution, the reaction essentially runs to completion forming the salt. Therefore, salts formed by the reaction of a strong acid with a strong base are neutral. NaCl formed by the neutralization of NaOH and HCl is a neutral salt. Salts formed by the reaction of a strong acid with a weak base are acidic, and salts formed by the reaction of a weak acid with a strong base are basic. This is due to the equilibrium the conjugate has with its acid or base. For example, sodium bicarbonate NaHCO₃ contains the conjugate of the weak acid H₂CO₃. The conjugate will reform the acid through the equilibrium: \[ \text{HCO}_3^- \, (\text{aq}) + \text{H}_2\text{O} \, (\text{aq}) \leftrightarrows \text{H}_2\text{CO}_3 \, (\text{aq}) + \text{OH}^- \, (\text{aq}) \] and, thus, acts as a weak base. A solution of NaHCO₃ yields a basic solution. If a salt is derived from a weak acid and a weak base, the pH of the solution depends on the relative acid strength (\(K_a\)) of the cation and base strength (\(K_b\)) of the anion. If \(K_a > K_b\), the solution of the salt is acidic. If \(K_a < K_b\), it is basic. If \(K_a \approx K_b\), it is neutral. ### Part A Given that at 25.0°C: - \(K_a\) for HCN is \(4.9 \times 10^{-10}\) and - \(K_b\) for NH₃ is \(1.8 \times 10^{-5}\). Calculate: - \(K_b\) for CN⁻ and - \(K_a\) for NH₄⁺. Enter the \(K_b\) value for CN⁻ followed by the
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