Given that at 25.0 °C K for HCN is 4.9 x 10 10 and K for NH3 is 1.8 x 10 , calculate K for CN and Ka for NH,+ Enter the Kp value for CN followed by the K, value for NH4, separated by a comma, using two significant figures. • View Available Hint(s) ΑΣφ Submit
Given that at 25.0 °C K for HCN is 4.9 x 10 10 and K for NH3 is 1.8 x 10 , calculate K for CN and Ka for NH,+ Enter the Kp value for CN followed by the K, value for NH4, separated by a comma, using two significant figures. • View Available Hint(s) ΑΣφ Submit
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
8

Transcribed Image Text:Salt is an ionic compound that is produced when a cation
and an anion from an acid-base reaction combine, and
solutions of salts can be neutral, acidic, or basic, depending
on the acid-base properties of the constituent cations and
anions.
Since strong acids and bases completely ionize in solution,
the reaction essentially runs to completion forming the salt.
Therefore, salts formed by reaction of a strong acid with a
strong base are neutral. NaCl formed by the neutralization
of NaOH and HCl is a neutral salt.
Salts formed by reaction of a strong acid with a weak base
are acidic, and salts formed by reaction of a weak acid with
a strong base are basic. This is due to the equilibrium the
conjugate has with its acid or base. For example, sodium
bicaronate NaHCO3 contains the conjugate of the weak
acid H2CO3. The conjugate will reform the acid through
the equilibrium
HCO, (aq)+ H20(aq) = H2CO3 (aq) + HO (aq)
and, thus, acts as a weak base. A solution of NaHCO3
yields a basic solution.
If a salt is derived from a weak acid and a weak base, the
pH of the solution depends on the relative acid strength (
K)of the cation and base strength (Kp) of the anion. If
Ka> Kb, the solution of the salt is acidic. If Ka <K, it
is basic. If K K, it is neutral.
Part B
Provide F
![ending
and
Part A
Given that at 25.0 °C
olution,
che salt.
with a
alization
K, for HCN is 4.9 × 10 10 and
K for NH3 is 1.8 × 10,
calculate
K, for CN and
Ka for NH,
eak base
k acid with
prium the
e, sodium
the weak
Ed through
Enter the Kp value for CN followed by the K, value for NH,, separated by a comma, using two significant figures.
• View Available Hint(s)
+ HO (aq)
HV ΑΣφ
圖] ?
NaHCO3
veak base, the
acid strength (
of the anion. If
E. If Ka < Kb, it
Submit
Part B Complete previous part(s)
Provide Feedback](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff26dfc9f-7a45-4802-bf6e-7276425e460e%2F2720028a-66f5-46e4-8efd-8e049523da27%2Fvm1g43j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ending
and
Part A
Given that at 25.0 °C
olution,
che salt.
with a
alization
K, for HCN is 4.9 × 10 10 and
K for NH3 is 1.8 × 10,
calculate
K, for CN and
Ka for NH,
eak base
k acid with
prium the
e, sodium
the weak
Ed through
Enter the Kp value for CN followed by the K, value for NH,, separated by a comma, using two significant figures.
• View Available Hint(s)
+ HO (aq)
HV ΑΣφ
圖] ?
NaHCO3
veak base, the
acid strength (
of the anion. If
E. If Ka < Kb, it
Submit
Part B Complete previous part(s)
Provide Feedback
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