8 Salt is an ionic compound that is produced when a cationand an anion from an acid-base reaction combine, andsolutions of salts can be neutral, acidic, or basic, dependingon the acid-base properties of the constituent cations andanions.Since strong acids and bases completely ionize in solution,the reaction essentially runs to completion forming the salt.Therefore, salts formed by reaction of a strong acid with astrong base are neutral. NaCl formed by the neutralizationof NaOH and HCl is a neutral salt.Salts formed by reaction of a strong acid with a weak baseare acidic, and salts formed by reaction of a weak acid witha strong base are basic. This is due to the equilibrium theconjugate has with its acid or base. For example, sodiumbicaronate NaHCO3 contains the conjugate of the weakacid H2CO3. The conjugate will reform the acid throughthe equilibriumHCO, (aq)+ H20(aq) = H2CO3 (aq) + HO (aq)and, thus, acts as a weak base. A solution of NaHCO3yields a basic solution.If a salt is derived from a weak acid and a weak base, thepH of the solution depends on the relative acid strength (K)of the cation and base strength (Kp) of the anion. IfKa> Kb, the solution of the salt is acidic. If Ka endingandPart AGiven that at 25.0 °Colution,che salt.with aalizationK, for HCN is 4.9 × 10 10 andK for NH3 is 1.8 × 10,calculateK, for CN andKa for NH,eak basek acid withprium thee, sodiumthe weakEd throughEnter the Kp value for CN followed by the K, value for NH,, separated by a comma, using two significant figures.• View Available Hint(s)+ HO (aq)HV ΑΣφ圖] ?NaHCO3veak base, theacid strength (of the anion. IfE. If Ka < Kb, itSubmitPart B Complete previous part(s)Provide Feedback

For weak acid and its conjugate base and similarly for a weak base and its conjugate acid- Ka × Kb =…

Given that at 25.0 °C K for HCN is 4.9 x 10 10 and K for NH3 is 1.8 x 10 , calculate K for CN and Ka for NH,+ Enter the Kp value for CN followed by the K, value for NH4, separated by a comma, using two significant figures. • View Available Hint(s) ΑΣφ Submit

Given that at 25.0 °C K for HCN is 4.9 x 10 10 and K for NH3 is 1.8 x 10 , calculate K for CN and Ka for NH,+ Enter the Kp value for CN followed by the K, value for NH4, separated by a comma, using two significant figures. • View Available Hint(s) ΑΣφ Submit

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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