Given: PCI5(g) What would be the equilibrium concentration of PCI5(g) if 0.20 mole of PCI5(g) was placed in a 1.00-L container at this temperature? What would be the new equilibrium concentration of PCI5(g) if the volume vere halved at this same temperature? = PCI3(g) + Cl2(g) Kc = 0.040 at 450°C

Given: PCI5(g) What would be the equilibrium concentration of PCI5(g) if 0.20 mole of PCI5(g) was placed in a 1.00-L container at this temperature? What would be the new equilibrium concentration of PCI5(g) if the volume vere halved at this same temperature? = PCI3(g) + Cl2(g) Kc = 0.040 at 450°C

World of Chemistry, 3rd edition

3rd Edition

ISBN:9781133109655

Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Chapter17: Equilibrium

Section: Chapter Questions

Problem 38A

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