Given: NL bisects ZKNM and ZKLM Prove: ANKLANML 1. NL bisects ZKNM and ZKLM 2. LKNLMNL 3. ZKLN ZMLN 4. NL LN 5. ANKLANML 1. Given N 5. ? K 2. Definition of angle bisector 3.? 4. ? M L

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Question

Justify the last three steps of the proof:                                                                         3.?                                                                                                                              4.?                                                                                                                              5.?

Given: NL bisects ZKNM and KLM
Prove: ANKL= ANML
1. NL bisects <KNM and KLM
2. ZKNL ZMNL
3. ZKLN ZMLN
4. NL LN
5. ANKL ANML
4. ?
K
Z
M
1. Given
2. Definition of angle bisector
3. ?
5. ?
N
L
Transcribed Image Text:Given: NL bisects ZKNM and KLM Prove: ANKL= ANML 1. NL bisects <KNM and KLM 2. ZKNL ZMNL 3. ZKLN ZMLN 4. NL LN 5. ANKL ANML 4. ? K Z M 1. Given 2. Definition of angle bisector 3. ? 5. ? N L
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