Given: NA EA A-(1030.00 N, 990.00 E), B (1040.00 N, 1120.00 E) ZA= 51° 54'41", ZB = 53° 12'46" AC = 108.16, BC = 106.30 Find: 0) Angle reference of AB to East 4°23'55" 1) Angle reference of AC to North and then coordinates of C from AC 2) Angle reference of BC to North and then coordinates of C from BC N 334124" 108:16 106.30 IN
Given: NA EA A-(1030.00 N, 990.00 E), B (1040.00 N, 1120.00 E) ZA= 51° 54'41", ZB = 53° 12'46" AC = 108.16, BC = 106.30 Find: 0) Angle reference of AB to East 4°23'55" 1) Angle reference of AC to North and then coordinates of C from AC 2) Angle reference of BC to North and then coordinates of C from BC N 334124" 108:16 106.30 IN
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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
Transcribed Image Text:Given:
NA FA
A-(1030.00 N, 990.00 E), B (1040.00 N, 1120.00 E)
ZA = 51° 54'41", ZB = 53° 12'46"
AC = 108.16, BC = 106.30
Find:
0) Angle reference of AB to East 4°23'55
1) Angle reference of AC to North and then coordinates of C from AC
2) Angle reference of BC to North and then coordinates of C from BC
N
108.16
A
33°4124"
30136
C
1040 106.30
2. NC = NB + BC COS
1120 106.30
ECC EB-BC Sin
E 4.40
ΑΝ
106.30 IN
Plan View
1. NC= NA + AC COS 33° 41' 24" = 11200000
ELEEA+AL Sin 33° 41'24" = 1050.00
B
S
= 1120.00
= 1050.00
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