Given n= 35 and o = 13, the margin of error at 2% alpha level is + Blank 1
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- A researcher wishes to try three different techniques to lower the blood pressure of individuals diagnosed with high blood pressure. Fifteen subjects are randomly assigned to three groups: the first group takes medication, the second group exercises, and the third group follows a special diet. Each group is assigned five subjects. After four weeks, the reduction in each person’s blood pressure is recorded. The data collected are shown in the table. Test the claim that there is no difference among means at α=0.05. Medication Exercise Diet 6 10 7 14 10 6 15 9 5 14 5 8 13 6 6 1. What is the null and alternative hypothesis?2. In the decision rule: Reject H0 if Fc>F0.05,(A,B)=C .Otherwise, fail to reject H0. a. What is the value for df for treatments, A? b. What is the value for df for error, B? c. What is the critical value, C?An airline claims that 90% of lost luggage is returned to its owners within 24 hours. A manager from this company has decided to test this and followed a random sample of 140 lost luggage reports. In 117 cases out of 140, the lost luggage was reunited with its owners within a 24 hour period. alpha = 1% significance Determine the power at p=92% and p=88%. I need the answer for power. Please solve for power onlyOn March 2005, a poll surveyed 535 adults aged 18 years old or older and asked “ Do you think there is life on other planets or not?. Of the 535, 326 responded yes. same question was asked on September3,2000, 385 of the 535 individuals surveyed said yes. Can you conclude that the proportion has decreased at alpha = 0.05 level of significance.
- A manufacturer claims that it has increased the shelf life of a line of cake mixes. Past records indicate that the average shelf life of the mix is 216 days. After a revised mix has been developed, a sample of six boxes of cake mix gave these shelf lives (in days): 215, 217, 218, 219, 216, and 217.Using α = 0.05, test the manufacturer claim that the shelf life of the cake mix is more than 216 days. a- Standard Deviation b- Testing a mean, Calculated c- Critical mean, Table d- p-value e-What do we conclude?A set of n = 10 pairs of scores has ΣX = 20, ΣY = 30, and ΣXY = 74. What is the value of SP for these data?Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 138 to 188 cm and weights of 40 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 167.61 cm, y = 81.52 kg, r=0.271, P-value=0.006, and y = -103 +1.18x. Find the best predicted value of ŷ (weight) given an adult male who is 155 cm tall. Use a 0.10 significance level. The best predicted value of y for an adult male who is 155 cm tall is (Round to two decimal places as needed.) kg.
- If a sample of n = 25 scores is selected from a normal population with µ = 100 and σ = 20, then the sample mean is expected to be around M = 100. Find the exact range of values that will contain the sample mean 80% of the time.Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 137 to 189 cm and weights of 37 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 167.50 cm, y =81.41 kg, r=0.232, P-value = 0.020, and y = - 109 + 1.17x. Find the best predicted value of y (weight) given an adult male who is 145 cm tall. Use a 0.01 significance level. The best predicted value of y for an adult male who is 145 cm tall is kg. (Round to two decimal places as needed.)Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 137 to 192 cm and weights of 40 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 167.80 cm, y = 81.45 kg, r=0.211, P-value = 0.035, and y = -103 +1.07x. Find the best predicted value of ŷ (weight) given an adult male who is 145 cm tall. Use a 0.01 significance level. The best predicted value of y for an adult male who is 145 cm tall is (Round to two decimal places as needed.) kg.
- Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 135 to 191 cm and weights of 39 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 167.76 cm, y = 81.33 kg, r= 0.212, P-value = 0.034, and y = - 105+ 1.03x. Find the best predicted value of y (weight) given an adult male who is 139 cm tall. Use a 0.10 significance level. The best predicted value of y for an adult male who is 139 cm tall is kg (Round to two decimal places as needed.)A nationwide survey in 2001 revealed that U.S. grade-school children spend an average of µ = 8.0 hours per week doing homework. The distribution is normal with σ = 2.5. Last year, a sample of n = 100 grade-school children was given the same survey. For this sample, the mean number of homework hours was 7.4. Has there been a significant change in the homework habits of grade-school children? Test with α = .05. For each problem students will write out all steps of hypothesis testing: State the null and research hypotheses. Set the level of risk associated with the null hypothesis. Select the appropriate test statistic. Compute the test statistic value (called the obtained value). Determine the value needed for rejection of the null hypothesis using the appropriate table of critical values for the particular statistic. Compare the obtained value and the critical value. Make your decision