Given: m∠AOB=42∘ m∠EOF=66∘ Prove: m∠COD=72∘   Complete the proof.   It is given that m∠AOB=42∘ and m∠EOF=66∘ . By the , ∠EOF≅ ∠BOC . Therefore, m∠BOC=66∘ . By the , m∠AOC=108∘ , and by the , m∠AOC+m∠COD=180∘ . After application of the , m∠COD=72∘ .

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