It is given that m∠AOB=42∘ and m∠EOF=66∘. By the , ∠EOF≅ ∠BOC. Therefore, m∠BOC=66∘. By the , m∠AOC=108∘, and by the , m∠AOC+m∠COD=180∘. After application of the , m∠COD=72∘.
It is given that m∠AOB=42∘ and m∠EOF=66∘. By the , ∠EOF≅ ∠BOC. Therefore, m∠BOC=66∘. By the , m∠AOC=108∘, and by the , m∠AOC+m∠COD=180∘. After application of the , m∠COD=72∘.
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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It is given that m∠AOB=42∘ and m∠EOF=66∘. By the , ∠EOF≅ ∠BOC. Therefore, m∠BOC=66∘. By the , m∠AOC=108∘, and by the , m∠AOC+m∠COD=180∘. After application of the , m∠COD=72∘.
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