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Given Information: The two-link planar robot, у, ст -17 х, ст P 10 10 Calculation: The tip of robot is at P(x, y) = (-17, –1). у, ст -17 x, cm Po 10 10 Consider the figure, d = V(-17)2 + (-1)² = 17.029 cm tan (360° + a + 01) = : the angles a and 0j are negative = 360° + a + 0 = 183.366° > a + 0j = -176.63°

Given Information: The two-link planar robot, у, ст -17 х, ст P 10 10 Calculation: The tip of robot is at P(x, y) = (-17, –1). у, ст -17 x, cm Po 10 10 Consider the figure, d = V(-17)2 + (-1)² = 17.029 cm tan (360° + a + 01) = : the angles a and 0j are negative = 360° + a + 0 = 183.366° > a + 0j = -176.63°

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I dont understand how they got to -176.63. do you think you could work it out for me?

Given Information: The two-link planar robot, у. ст -17 х, ст 10 10 Calculation: The tip of robot is at P (x, y) = (-17,–1). y, cm -17 х, ст Po 10 10 02 Consider the figure, d = V(-17)2 + (-1)² = 17.029 cm tan (360° + a + 0) = : the angles a and 0j are negative > 360° + a + 01 183.366° → a + 01 –176.63°
Transcribed Image Text:Given Information: The two-link planar robot, у. ст -17 х, ст 10 10 Calculation: The tip of robot is at P (x, y) = (-17,–1). y, cm -17 х, ст Po 10 10 02 Consider the figure, d = V(-17)2 + (-1)² = 17.029 cm tan (360° + a + 0) = : the angles a and 0j are negative > 360° + a + 01 183.366° → a + 01 –176.63°
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