Given: EK, KO, and OE are midsegments of A MNY. Prove: The perimeter of A EKO =(MN + NY + YM). M Complete the following two-column proof. Statements Reasons 1. EK, KO, and OE are midsegments of a MNY. 1. Given 2. Triangle Midsegment Theorem 2. 3. The perimeter of A EKO = (EK + KO + 0E). 3. 4. Substitution 5. The perimeter of A EKO = (MN + NY + YM). 5.
Given: EK, KO, and OE are midsegments of A MNY. Prove: The perimeter of A EKO =(MN + NY + YM). M Complete the following two-column proof. Statements Reasons 1. EK, KO, and OE are midsegments of a MNY. 1. Given 2. Triangle Midsegment Theorem 2. 3. The perimeter of A EKO = (EK + KO + 0E). 3. 4. Substitution 5. The perimeter of A EKO = (MN + NY + YM). 5.
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Transcribed Image Text:14. Consider the diagram below.
Practice
CRM 2.1 - Lesson 7
Y
Given: EK, KO, and OE are
midsegments ofA MNY.
E
Prove: The perimeter of
A EKO = (MN + NY + YM).
M
N
Complete the following two-column proof.
Statements
Reasons
1. EK, KO, and OE are
midsegments of A MNY.
1. Given
2. Triangle Midsegment
2.
Theorem
3. The perimeter of
A EKO = (EK + KO + 0E).
4. Substitution
5. The perimeter of
A EKO = (MN + NY + YM).
5.
Answer Options:
Given; AEKO = MN +NY+YM); Definition of perimeter; Distributive Property;
EK = MN; OE =NY; KO = }YM; Substitution; AEKO = (MN + NY+ YM)
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