given chiral molecule, leaving us to find a way to make both enantiomers of a chiral produc fortunately for chemists) does not tend to provide both enantiomers om a single available enantiomeric starting material. Using a generic nucleophile, explair e could separately make either enantiomer alone from only one possible starting alcohol racemic mixtures allowed). For the record, neither direction is possible with a single ste om the alcohol. Nu OH

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### Question 3: 
Nature (unfortunately for chemists) does not tend to provide both enantiomers of a given chiral molecule, leaving us to find a way to make both enantiomers of a chiral product from a single available enantiomeric starting material. Using a generic nucleophile, explain how one could separately make either enantiomer alone from only one possible starting alcohol (i.e., no racemic mixtures allowed). For the record, neither direction is possible with a single step from the alcohol.

### Diagram Explanation:

The diagram illustrates the process involving a chiral molecule starting from an alcohol. The following steps are depicted:
1. The starting material, which is a benzene ring with an attached chiral center bearing an OH group.
2. This chiral center undergoes a reaction where the hydroxyl group (-OH) is replaced by a nucleophile (Nu).
3. The reaction proceeds to form two separate products, each having the nucleophile (Nu) attached at the chiral center, but in different orientations.

This visualization helps in understanding how to perform separate reactions to achieve each enantiomer from a single chiral starting alcohol, without resulting in a racemic mixture.
Transcribed Image Text:### Question 3: Nature (unfortunately for chemists) does not tend to provide both enantiomers of a given chiral molecule, leaving us to find a way to make both enantiomers of a chiral product from a single available enantiomeric starting material. Using a generic nucleophile, explain how one could separately make either enantiomer alone from only one possible starting alcohol (i.e., no racemic mixtures allowed). For the record, neither direction is possible with a single step from the alcohol. ### Diagram Explanation: The diagram illustrates the process involving a chiral molecule starting from an alcohol. The following steps are depicted: 1. The starting material, which is a benzene ring with an attached chiral center bearing an OH group. 2. This chiral center undergoes a reaction where the hydroxyl group (-OH) is replaced by a nucleophile (Nu). 3. The reaction proceeds to form two separate products, each having the nucleophile (Nu) attached at the chiral center, but in different orientations. This visualization helps in understanding how to perform separate reactions to achieve each enantiomer from a single chiral starting alcohol, without resulting in a racemic mixture.
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