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Given CH4 (g) + CI2 (g) ---à CH3CI (g) +CHI (g). Ten grams of CH4 and 40.0g of chlorine gas undergo a reaction that has a 75.0% yield. Calculate the mass (in grams) of chloromethane (CH3CI) formed.

Given CH4 (g) + CI2 (g) ---à CH3CI (g) +CHI (g). Ten grams of CH4 and 40.0g of chlorine gas undergo a reaction that has a 75.0% yield. Calculate the mass (in grams) of chloromethane (CH3CI) formed.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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1. What is the percent yield of the reaction: PCI3(g) + 3H20 () -а НЗРОЗ (aq) + 3HCI (aq) Where 20.0 g of phosphorous trichloride react with excess water to form 11.2 g HCI and phosphorous acid (H3PO3)? 2. Given CH4 (g) + C12 (g) --à CH3CI (g) +CHI (g). Ten grams of CH4 and 40.0g of chlorine gas undergo a reaction that has a 75.0% yield. Calculate the mass (in grams) of chloromethane (CH3CI) formed.
Transcribed Image Text:1. What is the percent yield of the reaction: PCI3(g) + 3H20 () -а НЗРОЗ (aq) + 3HCI (aq) Where 20.0 g of phosphorous trichloride react with excess water to form 11.2 g HCI and phosphorous acid (H3PO3)? 2. Given CH4 (g) + C12 (g) --à CH3CI (g) +CHI (g). Ten grams of CH4 and 40.0g of chlorine gas undergo a reaction that has a 75.0% yield. Calculate the mass (in grams) of chloromethane (CH3CI) formed.
Limiting/Excess Reactant Problem with % Yield 4KO,(6) + 2H,0(1) 4KOH(s) + 30,(g) If a reaction vessel contains 120.0 g of KO, and 47.0 g of H,O, how many grams of O, can be produced? 4KO,(s) + 2H,0(1) 4KOH(s) + 30,(g) -- Hide 47.0 g Based on: 120.0ke mel 3mnt-0, 32.0g O, 40,51 g0, KO, ко, 71.4mot-kO mote Based on: 47.0 0 mel-L0 3mol-0, 32.0g O, 1253 g0, 18.02 gHO 2 mel 0-mol-0, Question if only 35.2 g of O, were recovered, what was the percent yield? 35,2 x 100 86.9% yield 40.51 actual x100= theoretical 16
Transcribed Image Text:Limiting/Excess Reactant Problem with % Yield 4KO,(6) + 2H,0(1) 4KOH(s) + 30,(g) If a reaction vessel contains 120.0 g of KO, and 47.0 g of H,O, how many grams of O, can be produced? 4KO,(s) + 2H,0(1) 4KOH(s) + 30,(g) -- Hide 47.0 g Based on: 120.0ke mel 3mnt-0, 32.0g O, 40,51 g0, KO, ко, 71.4mot-kO mote Based on: 47.0 0 mel-L0 3mol-0, 32.0g O, 1253 g0, 18.02 gHO 2 mel 0-mol-0, Question if only 35.2 g of O, were recovered, what was the percent yield? 35,2 x 100 86.9% yield 40.51 actual x100= theoretical 16
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