Given: BD bisects ZABC and AB CB. Prove: AD CD. Step Statement Reason BD bisects LABC Given AB CB BD BD Select a Reason...

Q: 8. Given: 00, AB = CD Prove: AACW ADBW.Explain. State the used theorem. Use two-column proof. Sketch…

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Q: Use rhombus ABCD to answer the follwoing questions. AD= 10, AC=16, and mZABC = 130°

A: For the given Problem,   We use properties of rhombus, Opposite angles are equal Diagonals bisect at…

Q: Based on the diagram shown, which of the following statements is true? F 17 15 38 14 26 O AC is…

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Q: In the figure below, AB ED. Prove AABC ~ AEDC. E В C A D

A: Both triangle are equivalent by AAA.

Q: Given: AE and BD intersect at C. BA LCA and CD 1 ED. Prove: ABAC~AEDC Wo Statements Reasons…

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Q: Question Given: DE DF, AE LED and CFL FD. Prove: AADE ACDF. Step Statement DE DF AEED CF FD Reason…

A: It is given that.. To prove that .Let us draw the diagram as follows.

Q: 13 Given: Parallelogram ABCD, EFG, and diagonal DFB D. E A в Prove: ADEF~ ABGF

A: Similarity of triangle concept...,

Q: Gordon and Tess are trying to determine whether AABC and AFGE can be proven congruent through rigid…

A: From the given graph we can see that, if the coordinates of vertices in triangle ABC is (x,y) then…

Q: Why is AABCEAGHJ? B E ..... Choose the correct answer below. A. Since AC GJ and CB JH, AB must be…

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Q: D. 3 2. -8 -5 -4 -3 -1 n= 4 山

A: Given data is : What is the apothem. To define the apothem.

Q: 3. Find AB in 00 A A. 9 B. 18 C. 18/2 D. 9/2 0 18 . B

A: As we know that, radius of a circle when perpendicularly fall on a chord then it divide the chord…

Q: For A ABC, ĀB= BE and BD bisects LABC. Prove AABD =A CBD. し B

A: Side-Angle-Side Postulate (SAS postulate) : If two sides and the included angle (angle between these…

Q: Look at the diagram. V X Y Z

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Q: Let A = Land B = lí 3l Which one of the following is not symmetric? B = li -3) which one of the…

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Q: 9.)7 X-4 XF4)

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Q: 2 Frud the exact perimeter aud the avea of the sequeut. ( Refer to Secton 8.5 Example 2a, 120

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Q: 11 Given: ZF is comp. to ZFGJ. ZH is comp. to ZHGJ. GJ bisects ZFGH. Conclusion: ZF= ZH

A: Given:- ∠F is complementary to ∠FGJ ∠H is complementary to ∠HGJ GJ→ bisects ∠FGH. To prove:- ∠F≅∠H