Given any string, s, which of the following evaluates to Trues[0: len(s)] ==sl:]s[0:]%3D==s[0:0] == s[0]s[len(s)] == s[-1]

Answered: Given any string, s, which of the…

Given any string, s, which of the following evaluates to True s[O : len(s)] == s[:] s[0:] == s[0:0] == s[0] s[len(s)] s[-1] ==

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter7: Characters, Strings, And The Stringbuilder

Section: Chapter Questions

Problem 16RQ

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1. Let L = {w {a, b}* : w contains bba as a substring that starts in an odd numbered position in the string (where numbering starts at 1)}. For example, bbbbaaaab L, while bbbaaaab L. Show an NDFSM that accepts L
Please solve within 30 minutes
A substring in programming represents all characters from a string, between two specified indices. Given a variable string called seq, a student writes the following program that will generate all nonempty substrings of seq: for i in range(len(seq)) : # line 1 for j in range(i) : # line 2 print(seq[j:i]) # line 3 Which of the following changes make the above program correct? A. Program is correct as it is. B. Change line 1 to: for i in range(len(seq)+1) : C. Change line 3 to: print(seq[j:i+1]) D. Change line 2 to: for j in range(i+1) :
A3 = {w ∈ {1,0}* | every odd position in w is an 1}. Provide regular expression. explain in detail include possible strings and NFA
Write coment for this code: alphabet = "abcdefghijklmnopqrstuvwxyzæøå ABCDEFGHIJKLMNOPQRSTUVWXYZÆØÅ " l= len(alphabet) def encode (letter, key): pos = alphabet.find(letter) newpos = (pos + key) % l return alphabet[newpos] def decode(letter, key): pos = alphabet.find(letter) finnnewpos = (pos + key) % lreturn alphabet[newpos]print(encode("a", 17))print(decode("r", 17))key = 19 message = "hello world" 3def encrypt(secretemessage, key): output = ""for character in secretemessage : if character in alphabet: output = output + encode(character, key) else:output = output + character return outputmessage = 'qMOHPIZHQSSMHØQLHØQTHgHORfZMHTMSÆMZHNWZLQHRMOHMZHWXXØIØØHUMLHgHSWLM'key = 68output = ""def dekrypt(message, key):output = ""for character in message:if character in alphabet:output = output + decode(character, key)else:output = output + characterreturn outputprint(dekrypt(message, key))
Revorse the vewels def reverse_vowels(text): Given a text string, create and return a new string constructed by finding all its vowels (for simplicity, in this problem vowels are the letters found in the string 'aeiouAEIOU') and reversing their order, while keeping all other characters exactly as they were in their original positions. However, to make the result look prettier, the capitalization of each moved vowel must be the same as that of the vowel that was originally in the target position. For example, reversing the vowels of 'Ilkka' should produce 'Alkki' instead of 'alkkI'. Applying this operation to random English sentences seems to occasionally give them a curious pseudo-Mediterranean vibe. Along with many possible other ways to perform this square dance, one straightforward way to reverse the vowels starts with collecting all vowels of text into a separate list, and initializing the result to an empty string. After that, iterate through all positions of the original text.…
Revorse the vewels def reverse_vowels(text): Given a text string, create and return a new string constructed by finding all its vowels (for simplicity, in this problem vowels are the letters found in the string 'aeiouAEIOU') and reversing their order, while keeping all other characters exactly as they were in their original positions. However, to make the result look prettier, the capitalization of each moved vowel must be the same as that of the vowel that was originally in the target position. For example, reversing the vowels of 'Ilkka' should produce 'Alkki' instead of 'alkkI'. Applying this operation to random English sentences seems to occasionally give them a curious pseudo-Mediterranean vibe.Along with many possible other ways to perform this square dance, one straightforward way to reverse the vowels starts with collecting all vowels of text into a separate list, and initializing the result to an empty string. After that, iterate through all positions of the original text.…
DNA sequences are strings made of combinations of four letters: A, C, G, and T. A substring refers to a string that is a continuous segment of a larger string; in the context of DNA, this would be a fragment of our DNA sequence. Write a program that asks the user for two input strings: a complete DNA sequence a DNA fragment whose occurrence is to be found in our complete DNA sequence. The program must display the number of matches as the output. Make sure to validate that your sequence is a DNA sequence -- i.e., that it contains no letters aside from A, C, G, and T.
def emotify(string): a=string.split() l=len(a) for i in range(0,l): if(a[i]=="smile"): a[i]=":)" if(a[i]=="grin"): a[i]=":D" if(a[i]=="sad"): a[i]=":((" if(a[i]=="mad"): a[i]=">:(" print (*a) string1=input("Enter the string:\n") emotify(string1); please explain this code. this is python
Provide examples of how to find the first or last time a particular character appears: string(), stringchr ()
L={a"b"a" | n,m=1,2,3....} is given. ni m n Draw the derivation tree for the string aaaabbbaaaa.
A2 = {w ∈ {1,0}* |w contains an even number of 0s and each 0 is followed by at least one 111}. Provide regular expression. explain in detail include possible strings and NFA