Given any natural number ne N. Suppose that a, y> 0, then (z + y)2m > zn + 2ngn 1y 27n Proof: Suppose that S(n) corresponds to the statement. It is true for n = 1. Suppose it is true for n >1. Then (z + y)" (x + y)² (22m + 2na2n y) (z² + 2ay + y?) + 2nanly |3| Therefore S(n + 1) is true whenever S(n) is true. True False

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