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Given a steel with an ultimate Stress of 90 ksi, and an endurance limit(Se) of 45 ksi calculate the following: a) The endurance strength (S,) of a polished rotating specimen corresponding to 10° cycles to failure b) The expected life (N) of a polished rotating specimen under a completely reversed stress of 55 ksi f 09 S = a Nº (f Sm)² S. 0.88 0.86 а 0,84 (f Sut log 3 1 0.82 b = S. 0.8 0.78 0.76 70 80 90 100 110 120 130 140 150 160 170 180 190 200 S. kpsi

Given a steel with an ultimate Stress of 90 ksi, and an endurance limit(Se) of 45 ksi calculate the following: a) The endurance strength (S,) of a polished rotating specimen corresponding to 10° cycles to failure b) The expected life (N) of a polished rotating specimen under a completely reversed stress of 55 ksi f 09 S = a Nº (f Sm)² S. 0.88 0.86 а 0,84 (f Sut log 3 1 0.82 b = S. 0.8 0.78 0.76 70 80 90 100 110 120 130 140 150 160 170 180 190 200 S. kpsi

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Given a steel with an ultimate Stress of 90 ksi, and an endurance limit(Se) of 45 ksi calculate the following: a) The endurance strength (S;) of a polished rotating specimen corresponding to 10* cycles to failure b) The expected life (N) of a polished rotating specimen under a completely reversed stress of 55 ksi f 0.9 0.88 Se = a Nº 0.86 а Se (f Sut 0.84 1 b = 0.82 Se 0.8 0.78 0.76 70 80 90 100 110 120 130 140 150 160 170 180 190 200 S. kpsi
Transcribed Image Text:Given a steel with an ultimate Stress of 90 ksi, and an endurance limit(Se) of 45 ksi calculate the following: a) The endurance strength (S;) of a polished rotating specimen corresponding to 10* cycles to failure b) The expected life (N) of a polished rotating specimen under a completely reversed stress of 55 ksi f 0.9 0.88 Se = a Nº 0.86 а Se (f Sut 0.84 1 b = 0.82 Se 0.8 0.78 0.76 70 80 90 100 110 120 130 140 150 160 170 180 190 200 S. kpsi
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