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Given a singly linked list with all elements as integers, please sort it using insertion sort. public class ListNode {- int data; ListNode next;4 ListNode(int val) { - data val; - public class Sort {+ public ListNode insertLSort(ListNode head) // your code goes here

Given a singly linked list with all elements as integers, please sort it using insertion sort. public class ListNode {- int data; ListNode next;4 ListNode(int val) { - data val; - public class Sort {+ public ListNode insertLSort(ListNode head) // your code goes here

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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### Sorting a Singly Linked List Using Insertion Sort Given a singly linked list with all elements as integers, the following code demonstrates how to sort it using insertion sort. **Class Definition for ListNode** ```java public class ListNode { int data; ListNode next; ListNode(int val) { data = val; } } ``` The `ListNode` class represents each element in the singly linked list. It contains two fields: - `int data`: Stores the value of the node. - `ListNode next`: Points to the next node in the list. The constructor `ListNode(int val)` initializes the node with a given value. **Class Definition for Sort** ```java public class Sort { public ListNode insertLSort(ListNode head) { // your code goes here } } ``` The `Sort` class contains a method `insertLSort` that takes the head of a singly linked list and sorts the list using the insertion sort algorithm. The implementation details of the insertion sort should be placed inside this method. ### Explanation Insertion sort iterates through the list and for each node, it finds the correct position within the sorted part of the list. It repositions the node by adjusting the pointers rather than by swapping data between nodes. This makes it well-suited for linked lists where node-swapping can be complicated and inefficient. To implement the insertion sort: 1. **Create a dummy node** that acts as the new head of the sorted part of the list. 2. **Iterate through the original list**, and for each node, find the correct position in the sorted part. 3. **Adjust the pointers** to insert the node in the sorted part. This method ensures that each insertion operation takes linear time, leading to an overall time complexity of \(O(n^2)\) for the entire list where \(n\) is the number of nodes in the list. ### Implementation Steps 1. Initialize a dummy node to serve as the starting point of the sorted list. 2. Traverse the original list. 3. For each node, scan the nodes in the sorted list to find the appropriate spot. 4. Insert the node and adjust the pointers accordingly. By following the steps above, the singly linked list will be sorted using insertion sort.
Transcribed Image Text:### Sorting a Singly Linked List Using Insertion Sort Given a singly linked list with all elements as integers, the following code demonstrates how to sort it using insertion sort. **Class Definition for ListNode** ```java public class ListNode { int data; ListNode next; ListNode(int val) { data = val; } } ``` The `ListNode` class represents each element in the singly linked list. It contains two fields: - `int data`: Stores the value of the node. - `ListNode next`: Points to the next node in the list. The constructor `ListNode(int val)` initializes the node with a given value. **Class Definition for Sort** ```java public class Sort { public ListNode insertLSort(ListNode head) { // your code goes here } } ``` The `Sort` class contains a method `insertLSort` that takes the head of a singly linked list and sorts the list using the insertion sort algorithm. The implementation details of the insertion sort should be placed inside this method. ### Explanation Insertion sort iterates through the list and for each node, it finds the correct position within the sorted part of the list. It repositions the node by adjusting the pointers rather than by swapping data between nodes. This makes it well-suited for linked lists where node-swapping can be complicated and inefficient. To implement the insertion sort: 1. **Create a dummy node** that acts as the new head of the sorted part of the list. 2. **Iterate through the original list**, and for each node, find the correct position in the sorted part. 3. **Adjust the pointers** to insert the node in the sorted part. This method ensures that each insertion operation takes linear time, leading to an overall time complexity of \(O(n^2)\) for the entire list where \(n\) is the number of nodes in the list. ### Implementation Steps 1. Initialize a dummy node to serve as the starting point of the sorted list. 2. Traverse the original list. 3. For each node, scan the nodes in the sorted list to find the appropriate spot. 4. Insert the node and adjust the pointers accordingly. By following the steps above, the singly linked list will be sorted using insertion sort.
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