Given a series circuit with R= 20, L = 2 mH, and C = 5 uf, a) the resonant frequency is Hz (round off numerical answer without decimal point) b) the quality factor is (round off numerical answer without decimal point) c) the bandwidth is rad/sec (round off numerical answer without decimal point) d) if the R is changed to 0.2 0, Q ill be and BW will be rad/sec (round off numerical answer without decimal point)
Given a series circuit with R= 20, L = 2 mH, and C = 5 uf, a) the resonant frequency is Hz (round off numerical answer without decimal point) b) the quality factor is (round off numerical answer without decimal point) c) the bandwidth is rad/sec (round off numerical answer without decimal point) d) if the R is changed to 0.2 0, Q ill be and BW will be rad/sec (round off numerical answer without decimal point)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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![Given a series circuit with R = 2 0, L = 2 mH, and C = 5 uf,
a) the resonant frequency is
Hz (round off numerical answer without decimal point)
b) the quality factor is
(round off numerical answer without decimal point)
c) the bandwidth is
rad/sec (round off numerical answer without decimal point)
d) if the R is changed to 0.2 0, Q will be
and BW will be
rad/sec (round off numerical answer without decimal point)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F60d15296-9d17-405e-90c8-91ce153ac3db%2Fb471b23e-8a97-494b-b471-2eb7a64566f9%2Fj98g0y_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given a series circuit with R = 2 0, L = 2 mH, and C = 5 uf,
a) the resonant frequency is
Hz (round off numerical answer without decimal point)
b) the quality factor is
(round off numerical answer without decimal point)
c) the bandwidth is
rad/sec (round off numerical answer without decimal point)
d) if the R is changed to 0.2 0, Q will be
and BW will be
rad/sec (round off numerical answer without decimal point)
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