Given a second order linear homogeneous differential equation a₂(x)y" + a₁(x)y' + a₁(x)y=0 we know that a fundamental set for this ODE consists of a pair linearly independent solutions y₁, y2. But there are times when only one function, call it y₁, is available and we would like to find a second linearly independent solution. We can find y2 using the method of reduction of order. First, under the necessary assumption the a₂(x) #0 we rewrite the equation as Then the method of reduction of order gives a second linearly independent solution as and a solution y₁ = 2¹ Applying the reduction of order method to this problem we obtain the following So we have p(x) = y" + p(x)y' +q(x)y=0 p(x) = Sp(z)dz [= So the general solution to 9y" - 3y + 4y = 0 can be written as where C' is an arbitrary constant. We can choose the arbitrary constant to be anything we like. One useful choice is to choose C so that all the constants in front reduce to 1. For example, if we obtain Y2 = C'3e² then we can choose C = 1/3 so that y₂ = ²¹. Given the problem - dx = Y2(x) = Cy₁u = Cy₁ (x) y₁(x) = a₁(x) a₂(x)' 2) [²√² (2) and e-Sp(z)dz x²y" + 3xy - 24y = 0 y = C₁Y₁+C232 C₁ x^4 Sp(z)dz q(x) = dx = -dx y} (x) Finally, after making a selection of a value for C as described above (you have to choose some nonzero numerical value) we arrive at y2(x) = Cy₁u = +0₂ a₁(x) a₂(x)'
Given a second order linear homogeneous differential equation a₂(x)y" + a₁(x)y' + a₁(x)y=0 we know that a fundamental set for this ODE consists of a pair linearly independent solutions y₁, y2. But there are times when only one function, call it y₁, is available and we would like to find a second linearly independent solution. We can find y2 using the method of reduction of order. First, under the necessary assumption the a₂(x) #0 we rewrite the equation as Then the method of reduction of order gives a second linearly independent solution as and a solution y₁ = 2¹ Applying the reduction of order method to this problem we obtain the following So we have p(x) = y" + p(x)y' +q(x)y=0 p(x) = Sp(z)dz [= So the general solution to 9y" - 3y + 4y = 0 can be written as where C' is an arbitrary constant. We can choose the arbitrary constant to be anything we like. One useful choice is to choose C so that all the constants in front reduce to 1. For example, if we obtain Y2 = C'3e² then we can choose C = 1/3 so that y₂ = ²¹. Given the problem - dx = Y2(x) = Cy₁u = Cy₁ (x) y₁(x) = a₁(x) a₂(x)' 2) [²√² (2) and e-Sp(z)dz x²y" + 3xy - 24y = 0 y = C₁Y₁+C232 C₁ x^4 Sp(z)dz q(x) = dx = -dx y} (x) Finally, after making a selection of a value for C as described above (you have to choose some nonzero numerical value) we arrive at y2(x) = Cy₁u = +0₂ a₁(x) a₂(x)'
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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