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(y-x)=y-x+ 2; y=x+2√x+4 When y=x+2√x+4. Y' = Thus, in terms of x, (y-x)y' = y-x+2= Since the left and right hand sides of the differential equation are equal when x + 2√x+4 is substituted for y. y=x+2√x+4 is a soll Proceed as in Example 6, by considering simply as a function and give its domain. (Enter your answer using interval notation.) Then by considering as a solution of the differential equation, give at least one interval I of definition, 0 (-8.4) 8 (-8,04)

(y-x)=y-x+ 2; y=x+2√x+4 When y=x+2√x+4. Y' = Thus, in terms of x, (y-x)y' = y-x+2= Since the left and right hand sides of the differential equation are equal when x + 2√x+4 is substituted for y. y=x+2√x+4 is a soll Proceed as in Example 6, by considering simply as a function and give its domain. (Enter your answer using interval notation.) Then by considering as a solution of the differential equation, give at least one interval I of definition, 0 (-8.4) 8 (-8,04)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Verify that the indicated function y = p(x) is an explicit solution of the given first-order differential equation. (y-x)y=y-x+ 2; y=x+2√x+4 When y=x+2√x+4, y' = Thus, in terms of x, (y-x) = y-x+2= Since the left and right hand sides of the differential equation are equal when x + 2√x+4 is substituted for y. y=x+ 2√x+4 is a solution. Proceed as in Example 6, by considering o simply as a function and give its domain. (Enter your answer using interval notation.) Then by considering as a solution of the differential equation, give at least one interval I of definition, 0 (-8,4) O (-8,-4) 0 (-3,-4) ((-4, 0) 0 (-4,4) Need Help? Wash
Transcribed Image Text:Verify that the indicated function y = p(x) is an explicit solution of the given first-order differential equation. (y-x)y=y-x+ 2; y=x+2√x+4 When y=x+2√x+4, y' = Thus, in terms of x, (y-x) = y-x+2= Since the left and right hand sides of the differential equation are equal when x + 2√x+4 is substituted for y. y=x+ 2√x+4 is a solution. Proceed as in Example 6, by considering o simply as a function and give its domain. (Enter your answer using interval notation.) Then by considering as a solution of the differential equation, give at least one interval I of definition, 0 (-8,4) O (-8,-4) 0 (-3,-4) ((-4, 0) 0 (-4,4) Need Help? Wash
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