Given a saturated salt solution at equilibrium, which of the following occurs when a common ion relative to the dissolved salt is added to the solution? MnXm (s) Mm+ (aq) + Xn- (aq) Select one: A. The equilibrium shifts to the left, favoring formation of the ions, thereby decreasing the molar solubility of the salt. B. The equilibrium shifts to the left, favoring formation of the solid salt, thereby decreasing the molar solubility of the salt. C. The equilibrium shifts to the right, favoring formation of the solid salt, thereby decreasing the molar solubility of the salt. D. The equilibrium shifts to the right, favoring formation of the ions, thereby decreasing the molar solubility of the salt.

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Chapter1: Chemical Foundations
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Given a saturated salt solution at equilibrium, which of the following occurs when a common ion relative to
the dissolved salt is added to the solution?
MrXm (s)
+ X (aq)
Mm+
(aq)
Select one:
A. The equilibrium shifts to the left, favoring formation of the ions, thereby decreasing the molar
solubility of the salt.
B. The equilibrium shifts to the left, favoring formation of the solid salt, thereby decreasing the molar
solubility of the salt.
C. The equilibrium shifts to the right, favoring formation of the solid salt, thereby decreasing the
molar solubility of the salt.
D. The equilibrium shifts to the right, favoring formation of the ions, thereby decreasing the molar
solubility of the salt.
Transcribed Image Text:Given a saturated salt solution at equilibrium, which of the following occurs when a common ion relative to the dissolved salt is added to the solution? MrXm (s) + X (aq) Mm+ (aq) Select one: A. The equilibrium shifts to the left, favoring formation of the ions, thereby decreasing the molar solubility of the salt. B. The equilibrium shifts to the left, favoring formation of the solid salt, thereby decreasing the molar solubility of the salt. C. The equilibrium shifts to the right, favoring formation of the solid salt, thereby decreasing the molar solubility of the salt. D. The equilibrium shifts to the right, favoring formation of the ions, thereby decreasing the molar solubility of the salt.
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