4.15 LAB: Hailstone sequence

Given a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence:

If n is even, divide it by 2
If n is odd, multiply it by 3 and add 1 (i.e. 3n +1)
Continue until n is 1

Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character (\t), are printed per line.

The output format can be achieved as follows:
print(n, end='\t')

Ex: If the input is:

the output is:

25 76 38 19 58 29 88 44 22 11

34 17 52 26 13 40 20 10 5 16

8 4 2 1

My Code:

n = int(input())
print(n, end='\t')
i = 1
while n > 1:
if not i % 10:
print(n, end='\n')
if n % 2 == 0:
n = n//2
print(n, end='\t')
else:
n = 3*n+1
print(n, end='\t')
i += 1
print()

Output:

Screenshot attached!

=
zyBooks My library > DAT 210: Data Programming Languages home > 4.15: LAB: Hailstone sequence
Latest submission - 3:04 PM CDT on 10/10/22
Only show failing tests
1: Compare output
Output differs. See highlights below.
Input
Your output
Expected output
2: Compare output
25
Your output
25
34
8
Expected output
25
34
8
Input 1
1→
76
17
4
1
76
17
4
Special character legend
38
52
N
38
52
2
19
26
1→
19
26
1
58
13
58
13
Output is nearly correct, but whitespace differs. See highlights below. Special character legend
29
40
29
40
88
20
88
20
44
10
zyBooks catalog
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44
10
Total score: 0/10
22
5
22
5
0/2
0/2
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Raza Aamir

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