Use cin to read integers from input until 100 is read. For each remaining integer read before 100, if the integer is equal to 18,output "Value appears" followed by a newline and increment numOccurrences.Ex: If the input is 18 -2 18 18 100, then the output is:Value appearsValue appearsValue appears3 time(s)1 #include 2 using namespace std;34 int main() {5678910111213}int inputNumber;int numOccurrences;/* Your code goes here */cout << numOccurrences << " time(s)" << endl;return 0;

Answered: Use cin to read integers from input…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Use cin to read integers from input until 100 is read. For each remaining integer read before 100, if the integer is equal to 18,
output "Value appears" followed by a newline and increment numOccurrences.
Ex: If the input is 18 -2 18 18 100, then the output is:
Value appears
Value appears
Value appears
3 time(s)
1 #include <iostream>
2 using namespace std;
3
4 int main() {
5
6
7
8
9
10
11
12
13}
int inputNumber;
int numOccurrences;
/* Your code goes here */
cout << numOccurrences << " time(s)" << endl;
return 0;

Expert Solution

Step 1

The source code of the program

#include <iostream>
int main()
{
int num;
int numOccurrences = 0;
while (std::cin >> num && num != 100)
{
if (num == 18) {
std::cout << "Value appears" << std::endl;
numOccurrences++;
}
}
return 0;
}

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