Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Example: 1. pattern = "abba", str = "dog cat cat dog" should return true. 2. pattern = "abba", str = "dog cat cat fish" should return false. 3. pattern = "aaaa", str = "dog cat cat dog" should return false. 4. pattern = "abba", str = "dog dog dog dog" should return false. Notes: You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space. The code is partially finished, and you have to use the provided parameter name. Pseudocode is not accepted. Hint: You may find the usage of HashMap helpful for solving this problem. Map map = new HashMap(); map.put('a', “apple"); // add a pair map.get('a'); // return apple map. containskey('a'); // return true map.containsValue(“banana") // false Note: Your method should start with the required name and parameters: class PatternChecker { public boolean check(String pattern, String str) { // ... } }

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
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Chapter1: Computer Networks And The Internet
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Please answer the question in the screenshot. The language used here is Java. Please give the source code. 

Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such
that there is a bijection between a letter in pattern and a non-empty word in str. Example:
1. pattern = "abba", str = "dog cat cat dog" should return true.
2. pattern = "abba", str = "dog cat cat fish" should return false.
3. pattern = "aaaa", str = "dog cat cat dog" should return false.
4. pattern
= "abba", str = "dog dog dog dog" should return false.
Notes: You may assume pattern contains only lowercase letters, and str contains lowercase letters
separated by a single space. The code is partially finished, and you have to use the provided parameter
name. Pseudocode is not accepted.
Hint: You may find the usage of HashMap helpful for solving this problem.
Map<Character, String> map = new HashMap<Character, String>();
map.put('a', "apple"); // add a <key, val> pair
map.get('a'); // return apple
map. containsKey('a'); // return true
map.containsvalue(“banana") // false
Note: Your method should start with the required name and parameters:
class PatternChecker {
public boolean check(String pattern, string str) {
// ...
}
Transcribed Image Text:Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Example: 1. pattern = "abba", str = "dog cat cat dog" should return true. 2. pattern = "abba", str = "dog cat cat fish" should return false. 3. pattern = "aaaa", str = "dog cat cat dog" should return false. 4. pattern = "abba", str = "dog dog dog dog" should return false. Notes: You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space. The code is partially finished, and you have to use the provided parameter name. Pseudocode is not accepted. Hint: You may find the usage of HashMap helpful for solving this problem. Map<Character, String> map = new HashMap<Character, String>(); map.put('a', "apple"); // add a <key, val> pair map.get('a'); // return apple map. containsKey('a'); // return true map.containsvalue(“banana") // false Note: Your method should start with the required name and parameters: class PatternChecker { public boolean check(String pattern, string str) { // ... }
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