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Given a normal distribution with μ = 102 and o=10, and given you select a sample of n = 4, complete parts (a) through (d). a. What is the probability that X is less than 90? P(X<90) = 0.0082 (Type an integer or decimal rounded to four decimal places as needed.) b. What is the probability that X is between 90 and 91.5? P(90 < X<91.5) = 0.0097 (Type an integer or decimal rounded to four decimal places as needed.) c. What is the probability that X is above 102.2? P(X> 102.2) = 0.4840 (Type an integer or decimal rounded to four decimal places as needed.) d. There is a 69% chance that X is above what value? X= (Type an integer or decimal rounded to two decimal places as needed.)

Given a normal distribution with μ = 102 and o=10, and given you select a sample of n = 4, complete parts (a) through (d). a. What is the probability that X is less than 90? P(X<90) = 0.0082 (Type an integer or decimal rounded to four decimal places as needed.) b. What is the probability that X is between 90 and 91.5? P(90 < X<91.5) = 0.0097 (Type an integer or decimal rounded to four decimal places as needed.) c. What is the probability that X is above 102.2? P(X> 102.2) = 0.4840 (Type an integer or decimal rounded to four decimal places as needed.) d. There is a 69% chance that X is above what value? X= (Type an integer or decimal rounded to two decimal places as needed.)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Given a normal distribution with μ = 102 and o=10, and given you select a sample of n = 4, complete parts (a) through (d). a. What is the probability that X is less than 90? P(X<90) = 0.0082 (Type an integer or decimal rounded to four decimal places as needed.) b. What is the probability that X is between 90 and 91.5? P(90 < X<91.5) = 0.0097 (Type an integer or decimal rounded to four decimal places as needed.) c. What is the probability that X is above 102.2? P(X> 102.2) = 0.4840 (Type an integer or decimal rounded to four decimal places as needed.) d. There is a 69% chance that X is above what value? X= (Type an integer or decimal rounded to two decimal places as needed.)
Transcribed Image Text:Given a normal distribution with μ = 102 and o=10, and given you select a sample of n = 4, complete parts (a) through (d). a. What is the probability that X is less than 90? P(X<90) = 0.0082 (Type an integer or decimal rounded to four decimal places as needed.) b. What is the probability that X is between 90 and 91.5? P(90 < X<91.5) = 0.0097 (Type an integer or decimal rounded to four decimal places as needed.) c. What is the probability that X is above 102.2? P(X> 102.2) = 0.4840 (Type an integer or decimal rounded to four decimal places as needed.) d. There is a 69% chance that X is above what value? X= (Type an integer or decimal rounded to two decimal places as needed.)
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