Given a continuous random variable, X, with the following pdf:What is the mean of X, E(X)?1(a)(b)(c)(d)1|42|1c|3f(x) = 40,16(e) None of the above0≤x≤2otherwise

The probability density function pdf is. f(x)= x/4 , 0<x<2 0 o/w

Answered: Given a continuous random variable, X,…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Q1. let Y₁ < Y₂ < Y3 < Y4 < Y5 are the order statistics of the random sample of size 5 from the distribution : f(x) = 3x², 0
A random variable, X, has a pdf given by The expected value of Y is O a. 3/5 O b. 5/3 O c. 7/5 O A random variable Y, is related to X by Px(x) d. 7/3 = 1 -3 < x < 1. and 0 otherwise 4 Y = X²
A random sample of size n₁ = 14 is selected from a normal population with a mean of 76 and a standard deviation of 7. A second random sample of size n₂ = 9 is taken from another normal population with mean 71 and standard deviation 11. Let X₁ and X₂ be the two sample means. Find: (a) The probability that X₁ – X₂ exceeds 4. 1 2 (b) The probability that 4.3 ≤ X₁ – X2 ≤ 5.6. Round your answers to two decimal places (e.g. 98.76). (a) i (b) i
Q6 Let X be a random variable with mean μ and suppose the expected value E[(X – μ)²k] exists for some k ≥ 1. Show for any d > 0, that P(|X-μ ≥ d) ≤ E[(X − µ)²] d2k (HINT: Use an argument similar to that used to prove Chebyshev's inequality.)
A relatively rare disease D occurs with P(D)=0.01. There exists a diagnostic test such that: P(positive test | D)= 0.99 P(positive test | not D)=0.1 Using the bayes rule, what is P(D | positive test)?
Suppose the random variable T is the length of life of an object (possibly the lifetime of an electrical component or of a subject given a particular treatment). The hazard function hr(t) associated with the random variable T is defined by hr(t) = lims-o- P(t ≤ T
My Find the standard deviation of the discret probability dist x P(x) xp(x)) (x-M)² | (x-mipul 2 σ = √(x-M)² pxx) ટે О 0.21 10*0.21=0 /10-112 =. M= Exp(x) 1 0.30 1*0.3 = 0.3 2 0=49 EXP(X) =M
* Let E(X]Y = y) = 3y and var(X|Y = y) = 2, and let Y have the p. d. f. se-y if y > 0 fG) = {o otherwise Then the variance of X is

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS

Given a continuous random variable, X, with the fo What is the mean of X, E(X)? (a) (b) (c) S|TW|NA|TW|T 3 4 3 1 f(x) = (d) 6 (e) None of the above x 0. 0≤ x ≤ otherwi