A random sample of size n₁ = 14 is selected from a normal population with a mean of 76 and a standard deviation of 7. A secondrandom sample of size n₂ = 9 is taken from another normal population with mean 71 and standard deviation 11. Let X₁ and X₂ be thetwo sample means. Find:(a) The probability that X₁ – X₂ exceeds 4.12(b) The probability that 4.3 ≤ X₁ – X2 ≤ 5.6.Round your answers to two decimal places (e.g. 98.76).(a) i(b) i

Given Information: First: Sample size n1=14 Mean μ1=76 Standard deviation σ1=7 Second: Sample size…

Answered: A random sample of size n₁ = 14 is…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Assume that the random variable X is normally distributed with mean = 15 and standard deviation = 2. Let n = 4. Find P( > 16) and P( < 16).
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A recent survey of 1040 U.S. adults selected at random showed that 634 consider the occupation of firefighter to have very great prestige. Estimate the probability (to the nearest hundredth) that a U.S. adult selected at random thinks the occupation of firefighter has very great prestige.Step 1Recall that the probability of an event based on relative frequency uses the formulaprobability of event = relative frequency = fn,where f is the frequency of the event occurrence in a sample of n observations. A total of 1040 people were surveyed and 634 considered the occupation of firefighter to have very great prestige. Therefore, the sample size is n = . The event of interest is that a U.S. adult selected at random thinks the occupation of firefighter has very great prestige. Therefore, the frequency f is equal to the number of adults who the occupation of firefighter has very great prestige, so f = (0.6096 answer is incorrect.) .
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