Given: A<--> B  (ka & ka')  B <--> C  (kb& kb') so eq 1:   d[A]/dt = -ka[A] + ka'[B] eq 2:   d[B]/dt= ka[A] - ka'[B] - kb[B] + kb'[C] eq 3:   d[C]/dt= kb[B] - kb'[C]   Using steady state:    ka[A] + kb'[C] = ka'[B] + kb[B]   [B]= (ka[A] + kb'[C] ) / (ka' + kb) This can be inserted into equation 3   d[C]/dt = kb[B] - kb'[C] = kb((ka[A] + kb'[C] ) / (ka' + kb)) - kb'[C] Determine the k and k’, where the above mechanism is equivalent to the following: A ↔ C (k and k’) d[A]/dt= -k[A]+ k'[C] d[C]/dt= k[A] - k'[C] What is the simpilfied values of k & k'?

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Given:

A<--> B  (ka & ka') 

B <--> C  (kb& kb')

so

eq 1:   d[A]/dt = -ka[A] + ka'[B]

eq 2:   d[B]/dt= ka[A] - ka'[B] - kb[B] + kb'[C]

eq 3:   d[C]/dt= kb[B] - kb'[C]

 

Using steady state:    ka[A] + kb'[C] = ka'[B] + kb[B]  

[B]= (ka[A] + kb'[C] ) / (ka' + kb)

This can be inserted into equation 3

  d[C]/dt = kb[B] - kb'[C] = kb((ka[A] + kb'[C] ) / (ka' + kb)) - kb'[C]

Determine the k and k’, where the above mechanism is equivalent to the following: A ↔ C (k and k’)

d[A]/dt= -k[A]+ k'[C]

d[C]/dt= k[A] - k'[C]

What is the simpilfied values of k & k'? 

 

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