Need help with #2 ### Transcription for Educational Website---#### Calculation of Molar Mass:- **b. CO₂** - Carbon (C): \(12.01 \times 1 = 12.01\) - Oxygen (O): \(16.00 \times 2 = 32.00\) - Total: \(12.01 + 32.00 = 44.01\)- **c. CH₄** - Carbon (C): \(12.01 \times 1 = 12.01\) - Hydrogen (H): \(1.01 \times 4 = 4.04\) - Total: \(12.01 + 4.04 = 16.05\)- **d. Na₂SO₄** - Sodium (Na): \(22.99 \times 2 = 45.98\) - Sulfur (S): \(32.07 \times 1 = 32.07\) - Oxygen (O): \(16.00 \times 4 = 64.00\) - Total: \(45.98 + 32.07 + 64.00 = 142.05\)---#### Problem Solving:2. **Question:** C₄H₁₀ is the chemical formula for butane, used as lighter fluid. How many molecules of butane are in 3.75 moles? Solution: \[ 0.622 \, x \] Further calculations are not shown, but this setup indicates a step towards finding the number of molecules using Avogadro’s number.3. **Question:** Aspartame, C₁₄H₁₈N₂O₅, is used as an artificial sweetener. How many moles are in \(5.21 \times 10^{24}\) formula units?4. **Question:** What is the mass, in grams, of 1.8 moles of NaCl?The document seems to provide steps for molar mass calculations and problem setups related to moles and molecules.---Note: Yellow highlights indicate calculated totals. Further detailed calculations may be necessary for complete solutions.

2. Given: Number of moles = 3.75 We have to find the number of molecules in 3.75 moles of butane

Answered: 45.98+ 32.07 +64 = 142.05 2. C₂H₁ is…

45.98+ 32.07 +64 = 142.05 2. C₂H₁ is the chemical formula for butane, used as lighter fluid. How many molecules of butane are in 3.75 moles?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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