**Problem Statement:**Given a 46.0-V battery and 24.0-Ω and 97.0-Ω resistors, find the current when connected in parallel.**Task:**Provide the solution: ________ A**Solution Steps:**1. **Understand the Problem:** - A 46.0-volt battery is connected to two resistors in parallel: one with a resistance of 24.0 ohms and the other with a resistance of 97.0 ohms.2. **Calculate the Total Resistance:** - In a parallel circuit, the total resistance \( R_t \) can be calculated using the formula: \[ \frac{1}{R_t} = \frac{1}{R_1} + \frac{1}{R_2} \] - For \( R_1 = 24.0 \, \Omega \) and \( R_2 = 97.0 \, \Omega \), the calculation becomes: \[ \frac{1}{R_t} = \frac{1}{24} + \frac{1}{97} \] - Solve for \( R_t \).3. **Calculate the Total Current:** - Use Ohm's Law to find the current \( I \) using the formula: \[ I = \frac{V}{R_t} \] - Where \( V = 46.0 \, \text{V} \).4. **Provide the Numerical Solution:** - Plug in the values and calculate the result to find the current in amperes.

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Answered: Given a 46.0-V battery and 24.0 - Q and…

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter21: Circuits And Dc Instruments

Section: Chapter Questions

Problem 79PE: Construe! Your Own Problem Consider a rechargeable lithium cell that is to be used to power a...

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Given a 46.0-V battery and 24.0 - Q and 97.0 - Q resistors, find the current when connected in parallel.