Give the balanced cell equation and determine for the galvanic cells based on the following half-reactions. (Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.) H₂O₂ + 2H+ + 2e¯ → 2H₂O € = 1.78 V Cr₂O7² +14H+ +6e2 Cr³+ +7H₂O € € = 0.45 a. V + 2H+2eH₂ b. € 0.00 V La³+ + 3e →La € = -2.37 V €° = V + + = 1.33 V

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Give the balanced cell equation and determine & for the galvanic cells based on the following half-reactions.
(Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.)
H₂O2 + 2H+ + 2e → 2H₂O
Cr₂O7² +14H+ + 6e¯ →2 Cr³+ +7H₂O €
€ = 0.45
a.
b.
2H+ + 2e
La³+ + 3e
€ =
V
+
→H₂ € = 0.00 V
→La € = -2.37 V
V
+
€
= 1.78 V
= 1.33 V
Transcribed Image Text:Give the balanced cell equation and determine & for the galvanic cells based on the following half-reactions. (Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.) H₂O2 + 2H+ + 2e → 2H₂O Cr₂O7² +14H+ + 6e¯ →2 Cr³+ +7H₂O € € = 0.45 a. b. 2H+ + 2e La³+ + 3e € = V + →H₂ € = 0.00 V →La € = -2.37 V V + € = 1.78 V = 1.33 V
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