Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Give correct detailed Solution with explanation needed..show work..don't give Handwritten answer..don't use Ai for answering this
![The following values will be useful for the problems in this chapter.
Acid
HF
HNO2
CH3COOH
НОСІ
HOBr
HOCN
HCN
H2SO4
H2CO3
K
slightly acidic
slightly basic
Ka = 7.2 x 10-4
Ka = 4.5 x 10-4
Ka = 1.8 x 10-5
Ka = 3.5 x 10
8
-9
Ka = 2.5 x 10
Ka = 3.5 x 104
Ka = 4.0 x 10-10
Ka1 = very large
Ka2 = 1.2 x 10-2
Ka1 = 4.2 x 10-7
Ka2 = 4.8 x 10-11
A solution having a pH of 1.4 would be described as
distinctly basic
distinctly acidic
neutral
Substance or Species
NH3
(CH3)3N
[Co(OH2)61²+
[Fe(OH2)612+
[Fe(OH2)6]³+
[Be(OH2)4]2+
[Cu(OH2)4]2+
HBO2
(COOH)2
CH3NH2
K
Kb = 1.8 x 10-5
Kb = 7.4 x 10-5
Ka = 5.0 x 10-10
Ka = 3.0 x 10-10
Ka = 4.0 x 10-3
Ka = 1.0 x 10-5
Ka = 1.0 x 10-8
Ka = 6.0 x 10
Ka1 = 5.9 x 10-2
Ka2 = 6.4 x 10-5
Kb = 5.0 x 10-4
-10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc9c7b922-f151-49b1-915a-cf2d164e3966%2F97725c2c-67a3-418b-bfe4-8ba768b8acf7%2F9o0gkux_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The following values will be useful for the problems in this chapter.
Acid
HF
HNO2
CH3COOH
НОСІ
HOBr
HOCN
HCN
H2SO4
H2CO3
K
slightly acidic
slightly basic
Ka = 7.2 x 10-4
Ka = 4.5 x 10-4
Ka = 1.8 x 10-5
Ka = 3.5 x 10
8
-9
Ka = 2.5 x 10
Ka = 3.5 x 104
Ka = 4.0 x 10-10
Ka1 = very large
Ka2 = 1.2 x 10-2
Ka1 = 4.2 x 10-7
Ka2 = 4.8 x 10-11
A solution having a pH of 1.4 would be described as
distinctly basic
distinctly acidic
neutral
Substance or Species
NH3
(CH3)3N
[Co(OH2)61²+
[Fe(OH2)612+
[Fe(OH2)6]³+
[Be(OH2)4]2+
[Cu(OH2)4]2+
HBO2
(COOH)2
CH3NH2
K
Kb = 1.8 x 10-5
Kb = 7.4 x 10-5
Ka = 5.0 x 10-10
Ka = 3.0 x 10-10
Ka = 4.0 x 10-3
Ka = 1.0 x 10-5
Ka = 1.0 x 10-8
Ka = 6.0 x 10
Ka1 = 5.9 x 10-2
Ka2 = 6.4 x 10-5
Kb = 5.0 x 10-4
-10
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