Give a super increasing sequence (with four elements) of yourchoice and make it into a hard knapsack. m= (101) Using itencrypt message m = (1101) binary the and also decrypt it andrecover original plaintext.

Answered: Give a super increasing sequence (with…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Encrypt The following correspondence between letters and numbers is used in the Caesar cypher. a b d e f i k lm n o r u V W X y z 1 2 3 4 6 7 8 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 Encrypt the animal name zebra with the Caesar cypher with a key of 25. What is the encrypted animal name (enter a string of letters with no spaces)? Save Submit You have used 0 of 1 attempt Decrypt An animal name was encrypted with the scheme described above. The encrypted animal name is azmchbnns . What is the animal name? Save
for letter in encrypt: new_position=(alphabets.find(letter)-key)%len(alphabets) decrypt+=alphabets[new_position] print("Decrypted message:",decrypt) can you explain line by line what each method and function does
Use RSA cryptography with public key p = 11 q = 13 and e = 23 to encrypt your unique student number. You need to remove all the consecutive zeros in the middle of the student number, then divide your student number into the blocks of two-digits from left to right. Afterwards, you will need to encrypt the resulted list of numbers by RSA. For example, the student number 13060009867 becomes the list of [13, 6, 98, 67]. Then you need to directly encrypt the numbers 13, 6 , 98 and 67 by RSA.
In a special case of a permutation cipher, we take a message, M, and write its letters in an s× t table, in a row-major fashion, and then let the ciphertext be a column-major listing of the entries in the table. For example, to encrypt the message ATTACKATDAWN, using a 3 × 4 table, we would write the message as ATTA CKAT DAWN and then write down the ciphertext as ACDTKATAWATN. The secret key in this cryptosystem is the pair (s, t). How is decryption done in this cryptosystem? Also, how hard would it be to attack this cryptosystem using a ciphertext-only attack?
Encrypt the word WEST using p=53 and q=71. Choose e=3. (Map A - Z to 126 and perform the encryption one letter at a time.)
Using C programming language: A Transposition Cipher A very simple transposition cipher encrypt(S, N) can be described by the following rules: If the length of S is 1 or 2, then encrypt(S, N) is S. If S is a string of N characters s1 s2 s3... sN and k = N/2, then encrypt(S)= encrypt(sk sk−1... s2 s1 ,K)+ encrypt(sN sN−1... sk+1 ,N - K) where + indicates string concatenation. For example, encrypt("Ok", 2) = "Ok" and encrypt("12345678", 8) = "34127856". Write a program to implement this cipher. The input is a file that is guaranteed to have less then 2048 characters. Code structure might look like this: #define MAX_SIZE 2048char text_buffer[MAX_SIZE];int main(){ // read file into text_buffer encrypt(text_buffer, n); // print out text_buffer return 0;}
Encrypt The following correspondence between letters and numbers is used in the Caesar cypher. de fghij 2 3 4 5 6 k im p q stu x y z a n V 1 8 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 Encrypt the animal name zebra with the Caesar cypher with a key of 3. What is the encrypted animal name (enter a string of letters with no spaces)? Decrypt An animal name was encrypted with the scheme described in the previous question (it was encoded with the key 3). The encrypted animal name is pduprw. What is the animal name?
Can you please show the shifts for the encrypt & decrypt in this format? For example, like this : Example:ABCDEFGHIJKLMNOPQRSTUVWXYZ Row 1FGHIJKLMNOPQRSTUVWXYZABCDE Row 2 If the plaintext to encrypt is:THIS IS THE ANSWER The ciphertext becomes:YMNX NX YMJ FSXBJW This is for me to help understand and to redo the problem for studying. Thank you!!
Alice sets up an RSA public/private key, but instead of using two primes, she chooses three primes p, q, and r and she uses n=pqr as her RSA-style modulus. She chooses an encryption exponent e and calculates a decryption exponent d. Encryption and Decryption are defined: C ≡ me mod n and m ≡ Cd mod n where C is the ciphertext corresponding to the message m. Decryption: de ≡ 1 mod φ(n) | Let p = 5, q = 7, r = 3, e = 11, and the decryption exponent d = -13. n = 105 & φ(n) = 48 Q: Alice upgrades to three primes that are each 200 digits long. How many digits does n have?
Encrypt The following correspondence between letters and numbers is used in the Caesar cypher. a b c d f h i j k lm n t V W e g 6. u y 0 1 2 3 4 7 8. 9. 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 Encrypt the animal name zebra with the Caesar cypher with a key of 3. What is the encrypted animal name (enter a string of letters with no spaces)? Decrypt An animal name was encrypted with the scheme described in the previous question (it was encoded with the key 3). The encrypted animal name is pduprw .What is the animal name?
You are to encrypt a ciphertext using the permutation p : {0,1}4 → {0,1}4 defined as p(x) = ~x, ie, toggle each bit (0 to 1 and 1 to 0). If you need an IV use 1010. If you need a nonce use 01. If the mode uses padding to handle arbitrary plaintext lengths, add 10* padding. If you need a counter, begin at 1. Encrypt the ciphertext 1110 1110 111 using ECB mode. Write four bits per box, with the final box possibly having fewer bits. Encrypt the ciphertext 1110 1110 111 using CBC mode. Write four bits per box, with the final box possibly having fewer bits. Encrypt the ciphertext 1110 1110 111 using CTR mode. Write four bits per box, with the final box possibly having fewer bits. Encrypt the ciphertext 1110 1110 111 using OFB mode. Write four bits per box, with the final box possibly having fewer bits.
A cryptography student has accidentally used the same keystream to encrypt two different messages, M1M1 and M2M2. We know that the ciphertexts are C1=0x4ab397cf20db1ce0C1=0x4ab397cf20db1ce0 and C2=0x2f7fded503744af5C2=0x2f7fded503744af5. We also happen to know that M1=0xbc66dac8daeee8e2M1=0xbc66dac8daeee8e2. a) What is M2M2 in hexadecimal? Please give your answer a leading 0x and use lowercase letters only. b) What is the keystream? Please give your answer a leading 0x and use lowercase letters only. Hint: These are all 8 byte numbers and will fit in an unsigned long type on most systems.

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Give a super increasing sequence (with four elements) of your choice and make it into a hard knapsack. m= (101) Using it encrypt message m = (1101) binary the and also decrypt it and recover original plaintext.