Give a definition of the first Newton's law 2. Two small spheres have equal charge of 40 nC and their centres are positioned on the x-axis: x-20 mm, and x-0mm. What is the force between the spheres? G
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- "Two charges q1 = 2.0 nC and q2 = 9.0 nC are placed at (x = 2.0 m, y = 0) and (x = 0, y = 8.0 m) respectively. What is the magnitude of the net electric field at the origin?" a. -1.3 x 10^18 N/C b. -1.01 x 10^19 N/C c. 1.26 x 10^18 d. 1.0 x 10^19 N/CTwo uncharged spheres are separated by 3.20 m. If 5.00 ✕ 1012 electrons are removed from one sphere and placed on the other, determine the magnitude of the Coulomb force (in N) on one of the spheres, treating the spheres as point charges. N HINT Find the net charge on each sphere and substitute values into Coulomb's law.Charge q₁ = 2.00 nC is at x₁ = 0 and charge q₂ = 5.50 nC is at x₂ = 2.00 m. At what point between the two charges is the electric field equal to zero? (Enter the x coordinate in m.) HINT Need Help? m Read It Watch It
- Plastic beads can often carry a small charge and therefore can generate electric fields. Three beads are oriented such that q2 is between q, and 93. The sum of the charge on 91 and 9, is 91 + 9, = -8.8 µc, and the net charge of the system of all three beads is zero. -E field lines 93 What charge does each bead carry? |-17.6 91 = What is the net charge of the system? What charges have to be equal? µc 8.8 92 = What is the net charge of the system? What charges have to be equal? µc 93 = 8.8In a thundercloud there are two equal and opposite charges ±48 C separated by 3.5 km. Assuming that they can be treated as point charges, what is the force between them? N20. I| What is the force F on the 1.0 nC charge in FIGURE EX22.20? Give your answer as a magnitude and a direction. 1.0 nC 1.0 cm, 1.0 cm 60° 60% 1.0 cm 2.0 nC -2.0 nC FIGURE EX22.20
- don't use chat gptQUESTION 2 Tw stationary protons experience a repulsive force of magnitude 2.50 x 10-9 N. What is the distance between the protons? The charge of a proton is 1.602 x 10-19 С. a. 6.13 x 10-10 m b. 1.66 x 10-10 m C. 2.11 x 10-10 m. d. 3.04 x 10-10 m e. 8.20 x 10-10 m.O 3 ll 94% i Particle A of charge 3.05 × 10-4 C is at the origin, 1:35 particle B of charge -6.10 x 10-4 c is at (4.44 m, 0) and particle C of charge 1.50 x 10-4 C is at (0, 3.06 m). (a) What is the x-component of the electric force exerted by A on C? N 39.08 (b) What is the y-component of the force exerted by A on C? N -135.80 (c) Find the magnitude of the force exerted by B on C. N (d) Calculate the x-component of the force exerted by B on C. (e) Calculate the y-component of the force exerted by B on C. N (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. (g) Repeat part (f) for the y-component. N (h) Find the magnitude and direction of the resultant electric force acting on C. magnitude direction counterciockwise trom the +x-axis Need Help? Rnad II
- A conducting massive sphere of radius a is surrounded by a thin conducting spherical shell of radius b as shown in the figure. The sphere (a) is grounded and the outer shell is charged with electric charge Q b a Find the electrostatic energy stored in the system (in SI units). Select one: Q² a. U ○ b. U = ○ C. U = ○ d. U = ○ e. U = ○ f. 8πEO U = Q2 8πε Q2 8πεο Q² όπερα Q² σπερ b- a ab b a +a a3 a Q² b-a 8πTEO b2 ×As shown below, an alpha particle (m = 6.642 × 10-27 kg, q = +2e) is shot upward with an initial speed of v; = 3.50 x 105 m/s from one large plate of charge toward another large plate of 8. charge. Each plate has a charge density given below. Assume gravity is negligible. а. Find the speed of the alpha particle once it hits the positively charged plate. b. Which plate is at the higher potential, the top plate or the bottom plate? Explain using physical reasonng. 02 = +2.50 µC/m² 2.00 mm V; = 3.50 × 10° m/s 01 = +4.50 µC/m²IP A particle with a mass of 4.0 g and a charge of +5.0x10-2 μC is released from rest at point A in the figure (Figure 1). Figure Ag 3.0 cm во 5.0 cm 4.0 cm OC E 1 of 1 L X > In which direction will this charge move? Positive Y- direction Negative y- direction Negative x-direction Positive x-direction Submit Part B V= Request Answer What speed will it have after moving through a distance of 5.5 cm ? The electric field has a magnitude of 1600 N/C Express your answer using two significant figures. 15. ΑΣΦ SFR P Pearson ? m/s