Gibbs energy change, A;G°, is related to cell potential, Eel, by the equation A;G° = -nFEl Part B where n is the number of moles of electrons transferred Calculate the standard cell potential at 25 °C for the reaction and F = 96 500 C mol1 is the Faraday's constant. X(s) + 2Y*(ag)→X²+(aq) + 2Y(s) where A¡H° = -675 kJ mol and A¡S° = -393 J K-1 mol-1. Express your answer to three significant figures and include the appropriate units. • View Available Hint(s) HA ? E = cell Value Units

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Gibbs energy change, A¡G° , is related to cell potential,
Eell, by the equation
A;G° = –nFEel
Part B
where n is the number of moles of electrons transferred
Calculate the standard cell potential at 25 ° C for the reaction
and F = 96 500 C mol1 is the Faraday's constant.
X(s) + 2Y*(ag)→+X²+(ag) +2Y(s)
where A,H° = -675 kJ mol1 and A,S° = -393 J K-1 mol-1
Express your answer to three significant figures and include the appropriate units.
• View Available Hint(s)
?
HA
Value
Units
%3D
cell
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Transcribed Image Text:Gibbs energy change, A¡G° , is related to cell potential, Eell, by the equation A;G° = –nFEel Part B where n is the number of moles of electrons transferred Calculate the standard cell potential at 25 ° C for the reaction and F = 96 500 C mol1 is the Faraday's constant. X(s) + 2Y*(ag)→+X²+(ag) +2Y(s) where A,H° = -675 kJ mol1 and A,S° = -393 J K-1 mol-1 Express your answer to three significant figures and include the appropriate units. • View Available Hint(s) ? HA Value Units %3D cell Submit Previous Answers X Incorrect; Try Again
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