Jack who weighs 68 kg is 45 years old and has severe hypomagnesaemia. He requires 0.26 g/kgof magnesium sulfate heptahydrate to be given intramuscularly over 4 hours.Magnesium Sulfate Concentrated Injection (2.465 g magnesium sulfate heptahydrate(MgSO4,7H₂O_MWt = 246.5) in each 5 mL ampoule) is to be diluted to 40 %w/v with 0.9%w/vsodium chloride solution.Calculate the volume of 0.9% sodium chloride solution that would be required. (Answer to 1decimal place.)Answer:

According to the question, Jack who weighs 68 kg is 45 years old and has severe hypomagnesaemia. He…

ghs 68 kg is 45 years old and has severe hypomagnesaemia. m sulfate heptahydrate to be given intramuscularly over 4 hou Fulfate Concentrated Injection (2.465 g magnesium sulfate hep MWt 246.5) in each 5 mL ampoule) is to be diluted to 40% de solution. = volume of 0.9% sodium chloride solution that would be requir

ghs 68 kg is 45 years old and has severe hypomagnesaemia. m sulfate heptahydrate to be given intramuscularly over 4 hou Fulfate Concentrated Injection (2.465 g magnesium sulfate hep MWt 246.5) in each 5 mL ampoule) is to be diluted to 40% de solution. = volume of 0.9% sodium chloride solution that would be requir

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

b Success Confirmation of Qu X < + с app.101edu.co Aktiv Chemistry X D2L Bar Graph Report - Spring x G The let-down reflex allows XCA. Fill words to blanks: Lon X Time's Up! The enthalpy of solution (AH) of KOH is -57.6 kJ/mol. If 1.56 g KOH is dissolved in enough water to make a 150.0 mL solution, what is the change in temperature (°C) of the solution? (The specific heat capacity of the solution is 4.184 J/g °C and the density of the solution is 1.02 g/mL). 1 4 7 +/- Untitled document - Google + 2 5 8 | °℃ 3 6 9 0 Update: Submit X C x 100
3. A S gram (NH4)2SO4 (MW = 132.14 g/mol) was dissolved to make 500mL solution. It found to have a density of 1.05 mL at 25 C. Find its concentration in: Molarity (M) = [A] Normality (N) = [B] %3D Molality (m) = [C]
Solubility (g of salt in 100 g H,O) KNOS 100 06 NANO 80 70 60 CaCl 50 Pb(NO)2 40 NaCl KCT 30 20 10 KCIO, Ce,(SO,), 10 20 30 40 50 60 70 80 90 100 Temperature (C) If 25.0 grams of K2Cr207 have been dissolved at 80oC, how many more grams are needed to create a saturated solution? Format BIU
Can you please answer number 7 and show all of the steps to the solution
olve Mass % of glucose ercentage of solu mass of solute (glucose) and the mass of solvent (water). age by using Equation 13.5. The mass of the soluti Solve ppm = mass glucose mass soln Comment The mass percentage of water in this solution is (100-11.9) % = 88.1%. 1 x 10g, 5.4 µg = 5.4 x 10g. b) Analyze In this case we are given the number of micrograms of solute. Because 1 µg is Plan We calculate the parts per million using Equation 13.6. 5.4 X 10-6 2.5 g mass of solute mass of soln Q X 100 = X 106 = 13.5 g 13.5 g + 100 g g X 100 = 11.9% X 106 = 2.2 ppm Practice Exercise 1 Calculate the mass percentage of NaCl in a solution containing 1.50 g of NaCl in 50.0 g of water. (a) 0.0291%, (b) 0.0300%, (c) 0.0513%, (d) 2.91%, (e) 3.00%. Practice Exercise 2 A commercial bleaching solution contains 3.62% by mass of sodium hypochlorite, NaOCI. What is the mass of NaOCl in a bottle containing 2.50 kg of bleaching solution? Mole Fraction, Molarity, and Molality Concentration expressions are often…
Can you please answer number 8 and show all of the steps to the solution
on 3 of 26 > O Macmillan Learning Isopropyl alcohol is mixed with water to produce a 34.0% (v/v) alcohol solution. How many milliliters of each component are present in 735 mL of this solution? Assume that volumes are additive. alcohol: A mL water: mL
Given: Mass of lauric acid (g): 8.000g Mass of benzoic acid (g): 1.027g Freezing temperature of pure lactic acid(°C): 43.3°C Freezing point of the benzoic acid-lauric acid mixture(°C): 39.8°C m of lauric acid: 1.8m Mols of benzoic acid solute: .0072mol Question: Calculate the experimental molecular weight of benzoic acid, in g/mol.
STRICTLY HANDWRITTEN ONLY... do ques 5... needed urgently...
12 of 19 View Available Hint(s) ? molarity of luminol solution : Value Units %3D
- 2022.pdf - Adobe Acrobat Pro DC (32-bit) ndow Help oter 14 - Soluti. x 2 / 3 100% 9) An aqueous solution has a normal boiling point of 103.0°C. What is the freezing point of this solution? For water Kb = 0.51°C/m and Kf=1.86°C/m. 9) A) -0.82°C B) -3.0°С С) -3.6°C D) -11°C 10) A solution of an 22.4 g of an unknown protein dissolved in enough water to make 0.150 L of solution has an osmotic pressure of 658 torr at 25°C. Based on these data, what is the molar mass of the protein? 10) search hp
Using molarity to find solute