A 10 g sample of Mg504 · 7H₂0 (246.489/mol) was heated in an oven at 105 °C until evaporated all the waters of hydration was off to generate Mg504 (mhydrous). The sample was then dissolved in 250 mL of distilled and diluted to a final volume of amount of 504 Water 0.5l. The in ppm in the final solution is ? > motor masses in g/mol → Mg5o4 · 71/₂0 = 2006 = > 246.48 H/₂0 = 18.02 لا
A 10 g sample of Mg504 · 7H₂0 (246.489/mol) was heated in an oven at 105 °C until evaporated all the waters of hydration was off to generate Mg504 (mhydrous). The sample was then dissolved in 250 mL of distilled and diluted to a final volume of amount of 504 Water 0.5l. The in ppm in the final solution is ? > motor masses in g/mol → Mg5o4 · 71/₂0 = 2006 = > 246.48 H/₂0 = 18.02 لا
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:A 10 g sample of Mg504 · 7H/₂0 (246.48 2/mp)
oven at 105 °C
was heated in an
until
all
the
waters of hydration was
evaporated
off to generate MgSO4 (mhydrous). The sample
was then dissolved in 250 mL of distilled
water and diluted to a final volume of
amount of 504²- in ppm in
0.56.
The
the final solution is
?
motor masses in g/mol = My5o4 · 71/₂0
7/₂0 = 206
246.48,
H/₂0 = 18.02
طلا
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