Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
Gauss's law: fEdi = Jin €0 Here E is the electric field vector, da is the surface element vector, qin is the total charge enclosed by the Gaussian surface, e, is the electric constant. The integral is taken over the closed Gaussian surface. • Electric potential at point P due to charge q is given by V = k2 4T€, r'

Gauss's law: fEdi = Jin €0 Here E is the electric field vector, da is the surface element vector, qin is the total charge enclosed by the Gaussian surface, e, is the electric constant. The integral is taken over the closed Gaussian surface. • Electric potential at point P due to charge q is given by V = k2 4T€, r'

icon
Related questions
Question
100%
Gauss's law: fE.da = qin €o Here E is the electric field vector, da is the surface element vector, qin is the total charge enclosed by the Gaussian surface, eo is the electric constant. The integral is taken over the closed Gaussian surface. • Electric potential at point P due to charge q is given by V = k2 %3D 4T€0 r' where r is the distance between the point P and the charge q. k = 9 x 10°NM2/C2, co = 8.854 x 10-12C²/(Nm2). • The power is defined by P = VI = I²R =V²/R
Transcribed Image Text:Gauss's law: fE.da = qin €o Here E is the electric field vector, da is the surface element vector, qin is the total charge enclosed by the Gaussian surface, eo is the electric constant. The integral is taken over the closed Gaussian surface. • Electric potential at point P due to charge q is given by V = k2 %3D 4T€0 r' where r is the distance between the point P and the charge q. k = 9 x 10°NM2/C2, co = 8.854 x 10-12C²/(Nm2). • The power is defined by P = VI = I²R =V²/R
1. (a) An insulating sphere has radius R and uniform volume charge density p. Calculate the electric field at the point P which is inside (r < R) and outside (r > R) of the sphere by using Gauss's law. Here r is the distance between the center of the sphere and the point P. (b) Discuss the possibility of choosing Gaussian surface other than the sphere. For instance what if you choose the cylindrical surface as a Gaussian sur- face, is it possible to use Gauss's law in order to calculate the electric field of a charged sphere? Explain your answer in detail.
Transcribed Image Text:1. (a) An insulating sphere has radius R and uniform volume charge density p. Calculate the electric field at the point P which is inside (r < R) and outside (r > R) of the sphere by using Gauss's law. Here r is the distance between the center of the sphere and the point P. (b) Discuss the possibility of choosing Gaussian surface other than the sphere. For instance what if you choose the cylindrical surface as a Gaussian sur- face, is it possible to use Gauss's law in order to calculate the electric field of a charged sphere? Explain your answer in detail.
Expert Solution
steps

Step by step

Solved in 4 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer