gas at 297 K, 1.018 atm and 0.800 L was heated to a final temperature of 336 K at constant pressure. How will you determine the final volume? New Volume =

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**Determining the Final Volume of Gas After Heating**

A gas at 297 K, 1.018 atm, and 0.800 L was heated to a final temperature of 336 K at constant pressure. How will you determine the final volume?

**New Volume =** 

[Input Field] / [Input Field] × [Input Field]

To determine the final volume of the gas, you can use the Charles's Law formula, which relates the temperature and volume of a gas at constant pressure. Charles's Law states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure remains constant. The formula is given by:

\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]

Where:
- \( V_1 \) is the initial volume
- \( T_1 \) is the initial temperature
- \( V_2 \) is the final volume
- \( T_2 \) is the final temperature

Rearranging the formula to solve for the final volume \( V_2 \):

\[ V_2 = V_1 \times \frac{T_2}{T_1} \]

Let's apply the given values:
- \( V_1 = 0.800 \) L
- \( T_1 = 297 \) K
- \( T_2 = 336 \) K

Substitute these into the formula:

\[ V_2 = 0.800 \, \text{L} \times \frac{336 \, \text{K}}{297 \, \text{K}} \]

Now, you can determine the final volume by evaluating the right-hand side of the equation.
Transcribed Image Text:**Determining the Final Volume of Gas After Heating** A gas at 297 K, 1.018 atm, and 0.800 L was heated to a final temperature of 336 K at constant pressure. How will you determine the final volume? **New Volume =** [Input Field] / [Input Field] × [Input Field] To determine the final volume of the gas, you can use the Charles's Law formula, which relates the temperature and volume of a gas at constant pressure. Charles's Law states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure remains constant. The formula is given by: \[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \] Where: - \( V_1 \) is the initial volume - \( T_1 \) is the initial temperature - \( V_2 \) is the final volume - \( T_2 \) is the final temperature Rearranging the formula to solve for the final volume \( V_2 \): \[ V_2 = V_1 \times \frac{T_2}{T_1} \] Let's apply the given values: - \( V_1 = 0.800 \) L - \( T_1 = 297 \) K - \( T_2 = 336 \) K Substitute these into the formula: \[ V_2 = 0.800 \, \text{L} \times \frac{336 \, \text{K}}{297 \, \text{K}} \] Now, you can determine the final volume by evaluating the right-hand side of the equation.
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