If an ideal gas has a pressure of 2.53 atm, a temperature of 19.10 .C, and a volume of 56.13 L, how many moles of gas are in the sample?|

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Chapter1: Chemical Foundations
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**Problem Statement:**

If an ideal gas has a pressure of 2.53 atm, a temperature of 19.10 °C, and a volume of 56.13 L, how many moles of gas are in the sample?

**Explanation:**

To solve this problem, we use the Ideal Gas Law, which is given by the equation:

\[ PV = nRT \]

Where:
- \( P \) is the pressure (in atm)
- \( V \) is the volume (in liters)
- \( n \) is the number of moles of gas
- \( R \) is the ideal gas constant (0.0821 L·atm/mol·K)
- \( T \) is the temperature (in Kelvin)

**Steps:**

1. **Convert the Temperature to Kelvin:**

   \[ T(K) = T(°C) + 273.15 \]
   \[ T(K) = 19.10 + 273.15 = 292.25 \text{ K} \]

2. **Rearrange the Ideal Gas Law to Solve for \( n \):**

   \[ n = \frac{PV}{RT} \]

3. **Plug in the Values:**

   \[ n = \frac{(2.53 \text{ atm})(56.13 \text{ L})}{(0.0821 \text{ L·atm/mol·K})(292.25 \text{ K})} \]

4. **Calculate \( n \):**

   After performing the calculation, you'll find the number of moles of gas in the sample. 

This approach helps understand how the properties of gases such as pressure, volume, and temperature are interrelated through the number of moles and the universal gas constant.
Transcribed Image Text:**Problem Statement:** If an ideal gas has a pressure of 2.53 atm, a temperature of 19.10 °C, and a volume of 56.13 L, how many moles of gas are in the sample? **Explanation:** To solve this problem, we use the Ideal Gas Law, which is given by the equation: \[ PV = nRT \] Where: - \( P \) is the pressure (in atm) - \( V \) is the volume (in liters) - \( n \) is the number of moles of gas - \( R \) is the ideal gas constant (0.0821 L·atm/mol·K) - \( T \) is the temperature (in Kelvin) **Steps:** 1. **Convert the Temperature to Kelvin:** \[ T(K) = T(°C) + 273.15 \] \[ T(K) = 19.10 + 273.15 = 292.25 \text{ K} \] 2. **Rearrange the Ideal Gas Law to Solve for \( n \):** \[ n = \frac{PV}{RT} \] 3. **Plug in the Values:** \[ n = \frac{(2.53 \text{ atm})(56.13 \text{ L})}{(0.0821 \text{ L·atm/mol·K})(292.25 \text{ K})} \] 4. **Calculate \( n \):** After performing the calculation, you'll find the number of moles of gas in the sample. This approach helps understand how the properties of gases such as pressure, volume, and temperature are interrelated through the number of moles and the universal gas constant.
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