Gas A and B are contained in a tube at 101.32 kPa pressure and 298.15 K . At one point the partial pressure of A is 80.79 kPa and at a point 0.03 maway, the partial pressure is 30.62 kPa . If the total pressure is constant throughout the tube, calculate the flux of A at steady state for equimolar counter diffusion. The diffusion coefficient is D = 0.230x10“ m²/s. a) 3.55×10³ kgmol A/m² -s b) 2.55×10³ kgmol A/m² -s c) 1.55×10° kgmol A/m² -s d) 4.55×10¬ kgmol A/m² -s
Gas A and B are contained in a tube at 101.32 kPa pressure and 298.15 K . At one point the partial pressure of A is 80.79 kPa and at a point 0.03 maway, the partial pressure is 30.62 kPa . If the total pressure is constant throughout the tube, calculate the flux of A at steady state for equimolar counter diffusion. The diffusion coefficient is D = 0.230x10“ m²/s. a) 3.55×10³ kgmol A/m² -s b) 2.55×10³ kgmol A/m² -s c) 1.55×10° kgmol A/m² -s d) 4.55×10¬ kgmol A/m² -s
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:Gas A and B are contained in a tube at 101.32 kPa pressure and 298.15 K . At one point
the partial pressure of A is 80.79 kPa and at a point 0.03 maway, the partial pressure is
30.62 kPa. If the total pressure is constant throughout the tube, calculate the flux of A at
steady state for equimolar counter diffusion.
The diffusion coefficient is D = 0.230×10“ m²/s.
a) 3.55x10 kgmol A/m² ·s
b) 2.55x103 kgmol A/m² -s
c) 1.55x10 kgmol A/m² -s
d) 4.55x10* kgmol A/m² · s
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