Problem 1: Find the equilibrium temperature attained by a porous surface soaked in Benzene. Assume that the porous material is facing downwards. The surrounding air, at pressure p = 101.325 kPa and temperature 310 K, is devoid of benzene. The porous surface is inside a room whose walls are at 310 K. The emissivity of the porous surface is 1.0. The vapor pressure of benzene is given by log10 (P) = 0.14591 (1) where P is in bar, and T is in K. The latent heat of vaporization at 298 K is 434 kJ/kg. The molecular mass of toluene is 78.11 kg/kmol, critical temperature and pressure are 562 K and 1.89 MPa respectively. 39.165 T - 261.236'
Problem 1: Find the equilibrium temperature attained by a porous surface soaked in Benzene. Assume that the porous material is facing downwards. The surrounding air, at pressure p = 101.325 kPa and temperature 310 K, is devoid of benzene. The porous surface is inside a room whose walls are at 310 K. The emissivity of the porous surface is 1.0. The vapor pressure of benzene is given by log10 (P) = 0.14591 (1) where P is in bar, and T is in K. The latent heat of vaporization at 298 K is 434 kJ/kg. The molecular mass of toluene is 78.11 kg/kmol, critical temperature and pressure are 562 K and 1.89 MPa respectively. 39.165 T - 261.236'
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:Problem 1: Find the equilibrium temperature attained by a porous surface soaked in
Benzene. Assume that the porous material is facing downwards. The surrounding air,
at pressure p= 101.325 kPa and temperature 310 K, is devoid of benzene. The porous
surface is inside a room whose walls are at 310 K. The emissivity of the porous surface
is 1.0. The vapor pressure of benzene is given by
39.165
log10(P) = 0.14591
(1)
T – 261.236'
where P is in bar, and T is in K. The latent heat of vaporization at 298 K is 434 kJ/kg.
The molecular mass of toluene is 78.11 kg/kmol, critical temperature and pressure are
562 K and 4.89 MPa respectively.
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