Garlic for Reducing Cholesterol In a test of the effectiveness of garlic for loweringcholesterol, 49 subjects were treated with raw garlic. Cholesterol levels were measured beforeand after the treatment. The changes (before minus after) in their levels of LDL cholesterol(in mg/dL) have a mean of 0.4 and a standard deviation of 21.0 (based on data from "Effectof Raw Garlic vs Commercial Garlic Supplements on Plasma Lipid Concentrations in Adultswith Moderate Hypercholesterolemia," by Gardner et al., Archives of Internal Medicine,Vol. 167, No. 4). Use a 0.05 significance level to test the claim that with garlic treatment, themean change in LDL cholesterol is greater than 0. What do the results suggest about the effec-tiveness of the garlic treatment?4.Insomnia Treatment A clinical trial was conducted to test the effectiveness of the drug zoni-fur.tm

From the provided information, The hypotheses can be constructed as: Null hypothesis: H0: µ = 0…

Answered: Garlic for Reducing Cholesterol In a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A clinical trial is run to assess the effects of different forms of regular exercise on HDL levels in persons between the ages of 18 and 29. Participants in the study are randomly assigned to one of three exercise groups (Weight training, Aerobic exercise or Stretching/Yoga) and instructed to follow the program for 8 weeks. Their HDL levels are measured after 8 weeks and are summarized below. Exercise Group N Mean Standard Deviation Weight Training 20 49.7 10.2 Aerobic Exercise 20 43.1 11.1 Stretching/Yoga 20 57.0 12.5 Is there a significant difference in mean HDL levels among the exercise groups? Run the test at a 5% level of significance. HINT: SSerror = 7286.5.
You wish to determine the average VO2max (maximum rate of oxygen consumption, often associated with athletic performance) of a sample of 100 Olympic athletes, and to use a quantitative metric to assess your confidence in the average (mean) value. You calculate a mean of 71 ml/kg/min and a variance of 26.06 from your sample. Question: What are the standard error of the mean (SEM) and the approximate 95% CI of the mean?
Weights of one-year-old male German Shepherd dogs have a standard deviation of 1.5 lbs. Determine the percentage of all samples of 200 one-year-old male German Shepherds that have mean weights within 0.125 lb of the population mean weight of all one-year-old German Shepherds.
Q2: Serum amylase determinations were made on a sample of 15 apparently healthy subjects in the Electricity Power Plant of Nasriya January 2010. The sample yielded a mean of 96 and a standard deviation of 35 units/100ml. Estimate the true mean of serum amylase in the healthy population of Nasriya.
This research was conducted with Korean adolescents in the Los Angeles area. Would you be willing to generalize the results of this study to Korean adolescents who live in other regions of the country? Why or why not.
We have seen that drinking tea appears to offer a strong boost to the immune system. In a study extending the results,' blood samples were taken on 5 participants before and after one week of drinking about five cups of tea a day (the participants did not drink tea before the study started). The before and after blood samples were exposed to e.coli bacteria, and production of interferon gamma, a molecule that fights bacteria, viruses, and tumors, was measured. Mean production went from 155 pg/mL before tea drinking to 448 pg/mL after tea drinking. The mean difference for the 5 subjects is 293 pg/mL with a standard deviation in the differences of 242. The paper implies that the use of the t-distribution is appropriate. 'Adapted from Kamath, A., et. al., “Antigens in tea-beverage prime human Vy2V82 T cells in vitro and in vivo for memory and non-memory antibacterial cytokine responses," Proceedings of the National Academy of Sciences, May 13, 2003; 100(10): 6009-6014. (a) Which method is…
Diabetes Plasma-glucose levels are used to determine the pres- ence of diabetes. Suppose the mean In (plasma-glucose) concentration (mg/dL) in 35- to 44-year-olds is 4.86 with standard deviation = 0.54. A study of 100 sedentary people in this age group is planned to test whether they have a higher or lower level of plasma glucose than the general population. 7.7 If the expected difference is 0.10 In units, then what is the power of such a study if a two-sided test is to be used with a = .05? 7.8 Answer Problem 7.7 if the expected difference is 0.20 In units. 7.9 How many people would need to be studied to have 80% power under the assumptions in Problem 7.7?
Citrus Rental is a popular car rental agency that has a history of having too few cars available, so that its available cars are overdriven. The mean monthly mileage over the years for Citrus cars has been about 1500 miles per month. Recently, though, Citrus purchased thousands of new cars, and the company claims that the average mileage of its cars is now less than in the past. To test this, a random sample of 11 recent mileages of Citrus cars was taken. The mean of these 11 mileages was 1332 miles per month, and the standard deviation was 232 miles per month. Assume that the population of recent monthly mileages of Citrus cars is normally distributed. At the 0.05 level of significance, can it be concluded that the mean recent monthly mileage, u, of Citrus cars is less than 1500 miles per month? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary,…
How do you find (b.)?
You are conducting a study to see if the accuracy rate for fingerprint identification is significantly different from 0.51. Thus you are performing a two-tailed test. Your sample data produce the test statistic - 2.153. Find the p-value accurate to Z = - 4 decimal places. p-value
15

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