Gannon University would like to test the claim that the proportion of women enrolled in the University has changed since 2014. In 2014 there were 60% women enrolled. Suppose in 2016 I sample 75 students and find that 50 of them are women. We would like to set the alpha to 0.05. 1. What is the hypothesis statement for this test? 2. What is the critical value for this hypothesis test? 3. What is the test statistic for this hypothesis test? 4. What is the p-value for this hypothesis test? 5. What is the conclusion for this hypothesis test?
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- The p-value for a hypothesis test turns out to be 0.00694. At a 9% level of significance, what is the proper decision? Reject H0H0 Fail to reject H0You may need to use the appropriate technology to answer this question. Consider the following hypothesis test. H0: ? = 100 Ha: ? ≠ 100 A sample of 65 is used. Identify the p-value and state your conclusion for each of the following sample results. Use ? = 0.05. (a) x = 104 and s = 11.5 Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. a.) Reject H0. There is insufficient evidence to conclude that ? ≠ 100. b.) Do not reject H0. There is sufficient evidence to conclude that ? ≠ 100. c.) Do not reject H0. There is insufficient evidence to conclude that ? ≠ 100. d.) Reject H0. There is sufficient evidence to conclude that ? ≠ 100. (b) x = 95.5 and s = 11.0 Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion.…The p-value for a hypothesis test turns out to be 0.00857. At a 8% level of significance, what is the proper decision? Reject H0H0 Fail to reject H0
- 26whats the test statistic for this hypothsis test AND P value hypothesis test5. A one-way ANOVA test is conducted and finds the following results: n = 34, K = 4, x̅ = 8.32, MST = 26.723, and MSE = 14.767. What is the test statistic, F, for this ANOVA test? B. 1.81 D. 3.69 C. 3.21 A. 1.77 6. A hypothesis test is conducted with H0 : p1 - p2 = 0 vs. Ha: p1 - p2 ≠ 0 . What is the tail area of the hypothesis test given the sample data: n1= 121, p1=0.79, n2= 81, p2 = 0.67 C. 0.0614 B. 0.0536 A. 0.0268 D. 0.0307
- A published report claims that 35% of college students have used an online dating site or app. Believing this claimed value is too low, a researcher surveys a random sample of n = 420 college students about their experiences with online dating sites and apps. A total of 166 of the surveyed students indicate that they have used online dating sites or apps. Use this information to conduct a hypothesis test at a significance (or alpha) level of 0.05. 1.Based on the test statistic you computed to answer Question 11, along with what you see in Table B, what should the P-value be? 2. Based on the P-value you obtained and how it compares to the significance level of 0.05, what is your conclusion? 3. Look again at your answer to Question 13. If a smaller significance level had been chosen—like 0.01—would you have reached a different conclusion? Please explain. 4. Again, look back at how you answered Question 13. If a larger significance level had been chosen—like 0.10—would you have…Use the random sample data to test the claim that 72% of students have internet access at home. Use 5% level of significance. Sample data: x = 158, n = 200 1. Identify the tail of the test. 2.Find the P-value 3.Will the null hypothesis be rejected? 4. Is the initial claim supported?Assume that, on the average, normal rhesus monkeys spend an mean of 60 minutes dreaming while sleeping at night (thus, μ = 60 minutes). Time spent dreaming is typically referred to as REM sleep (Rapid Eye Movement). You are interested in the effects a new dream-enhancing drug has on dreaming since an increase in the time spent dreaming while sleeping is thought to be a good thing in terms of getting a "restful" sleep. You want to pursue testing the drug in humans if there is any evidence that it significantly increases nightly dreaming time in these nonhuman primates. Ten rhesus monkeys are administered the drug in the morning and their dream time (in minutes) is monitored that night. The alternate hypothesis is: the drug will increase time spent dreaming, or the time in REM sleep. You obtain the following times (minutes) each monkey spent dreaming: 52, 69, 74, 60, 67, 65, 69, 55, 63, 68 Set alpha at a = .01, and complete step 4 of the hypothesis testing procedure, what decision should…
- Only about 14% of all people can wiggle their ears. Is this percent lower for millionaires? Of the 400 millionaires surveyed, 40 could wiggle their ears. What can be concluded at the a = 0.10 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: ? Select an answer V (please enter a decimal) H1: ? v Select an answer V (Please enter a decimal) c. The test statistic ? v (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 3 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... the null hypothesis. O The data suggest the population proportion is not significantly lower than 14% at a = 0.10, so there is statistically insignificant evidence to conclude that the population proportion of millionaires who can wiggle their ears is lower than 14%. O The data suggest the populaton proportion is significantly lower…I need to know am I correctWe want to conduct a hypothesis test of the claim that for middle-aged adults the population mean of their cholesterol levels is less than 191.7 mg dL mg dL mg a random sample of such levels. The sample has a mean of 190.7 dL -0 O It is unclear which test statistic to use. For each of the following sampling scenarios, choose an appropriate test statistic for our hypothesis test on the population mean. Then calculate that statistic. Round your answers to two decimal places. (a) The sample has size 110, and it is from a non-normally distributed population with a known standard deviation of 19.1. Oz = 0t= (b) The sample has size 14, and it is from a population with a distribution about which we know very little. 2-0 Oz= 01-0 O It is unclear which test statistic to use. and a standard deviation of 18 Explanation Check . We choos X Ⓒ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Cer