g(a)=a2 + a - 3 where a0=1, a1= 2 Above shows a function g(a) a. Sketch a graph of the function above b. Prove using the graph in a. above that the interval points at a0 & a1 have opposite signs. c. With the utilization of the Newton's method, do an estimation of the root preferably in four d.p(decimal places) of the equation that lies between the endpoints given.N.b iterations performed = two
g(a)=a2 + a - 3
where a0=1, a1= 2
Above shows a function g(a)
a. Sketch a graph of the function above
b. Prove using the graph in a. above that the interval points at a0 & a1 have opposite signs.
c. With the utilization of the Newton's method, do an estimation of the root preferably in four d.p(decimal places) of the equation that lies between the endpoints given.N.b iterations performed = two
The function is a rule that associates or fixes a number to the particular point a. The solution of the equation is the value of a, which satisfies the equation. In this problem the function is .
In the first part of the problem, we have to sketch the graph of the function, in the second part, we have to prove that the output of the functions has opposite values at and . In the final part of the equation we have to find the solution of the equation.
Step by step
Solved in 4 steps with 1 images