g) Find a 95% confidence interval on the mean of Y for the values of regressors from b). h) Find a 95% prediction interval on the power consumption for the values of regressors from b). i) Calculate R2 and adjusted R2 for this model. Interpret these quantities.

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Kindly help me with g) h) i) although I know the answer for i) R^2 = 0.7447 and Adjusted R square 0.5989. If you could help interpret it.

 

Here are the answers for the previous ques. for reference.

(a) Thus, the multiple linear regression line is,

y = (–102.7132) + 0.6054 x1 + 8.9236 x2 + 1.4375 x3 + 0.0136 x4

 

(b) y = (–102.7132) + 0.6054 (75) + 8.9236 (24) + 1.4375 (90) + 0.0136 (98)

   = (–102.7132) + 45.405 + 214.1664 + 129.375 + 1.3328

   = 287.566

 

(c) the P-value for the overall model is 0.030302769.

It is known that, if the P-value is less than or equal to the level of significance, then reject the null hypothesis. Or else, fail to reject the null hypothesis. Here, the level of significance is 0.05. Hence, the obtained P-value is less than the level of significance. Thus, the null hypothesis is rejected. Therefore, there is enough evidence to claim that the regression model is significant at 5% level of significance.

 

(d) The mean square error is the estimate value of population variance. From the output, MSE = 242.7156. Thus, estimated value of σ2 is 242.7156.

(e) For x1: From the output it is obtained that the P-value corresponding to the t-test of x1 is 0.1448, which is greater than the level of significance of 0.05. Hence, the null hypothesis is not rejected. Thus, there is not enough evidence to claim that there is significance relationship between x1 and y, when the other predictors are constant at 5% level of significance.

For x2: From the output it is obtained that the P-value corresponding to the t-test of x2 is 0.1361, which is greater than the level of significance of 0.05. Hence, the null hypothesis is not rejected. Thus, there is not enough evidence to claim that there is significance relationship between x2 and y, when the other predictors are constant at 5% level of significance.

For x3: From the output it is obtained that the P-value corresponding to the t-test of x3 is 0.5668, which is greater than the level of significance of 0.05. Hence, the null hypothesis is not rejected. Thus, there is not enough evidence to claim that there is significance relationship between x3 and y, when the other predictors are constant at 5% level of significance.

For x4: From the output it is obtained that the P-value corresponding to the t-test of x4 is 0.9857, which is greater than the level of significance of 0.05. Hence, the null hypothesis is not rejected. Thus, there is not enough evidence to claim that there is significance relationship between x4 and y, when the other predictors are constant at 5% level of significance.

(f) From the output, the 95% confidence interval for β1 is (–0.2669, 1.4777).

From the output, the 95% confidence interval for β2 is (–3.6101, 21.4574).

From the output, the 95% confidence interval for β3 is (–4.2178, 7.0927).

From the output, the 95% confidence interval for β4 is (–1.7216, 1.7488).

g) Find a 95% confidence interval on the mean of Y for the values of regressors from b).
h) Find a 95% prediction interval on the power consumption for the values of regressors from
b).
i) Calculate R2 and adjusted R2 for this model. Interpret these quantities.
Transcribed Image Text:g) Find a 95% confidence interval on the mean of Y for the values of regressors from b). h) Find a 95% prediction interval on the power consumption for the values of regressors from b). i) Calculate R2 and adjusted R2 for this model. Interpret these quantities.
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